C#用更具体的类型覆盖抽象属性 [英] C# Override abstract property with more specific type

问题描述

我有一个相当简单的问题，但我在任何地方都找不到合适的解决方案.我想在我的抽象父类中指定一个抽象对象 CustomValues 作为属性.但是，从它继承的类应该能够使用更具体的类型作为此属性 CustomValues 的对象.起初我以为我会通过一个接口来解决问题，但不幸的是，这也没有奏效.你怎么做这样的事情，它有效?

I have a rather simple problem, but I can't find a proper solution anywhere. I would like to specify an abstract object CustomValues as property in my abstract parent class. However, the class inheriting from it should be able to use a more specific type as an object for this property CustomValues. At first I thought I would solve the problem by an interface, but unfortunately that didn't work out either. How do you do something like that, that it works?

public abstract class MyAbstract {
    public abstract object CustomValues { get; set; }
}

public class MyImplementation : MyAbstract {
    public override MySpecificClass CustomValues { get; set; }
}

这会抛出三个错误:

• 缺少 getter 实现
• 缺少 setter 的实现
• 类型 object 和 MySpecificClass 之间的类型不匹配

• Missing implementation for getter
• Missing implementation for setter
• Type missmatch between type object and MySpecificClass

推荐答案

我认为您最初认为使用接口(+ 泛型)的想法是正确的.通常，您可能还想添加类型约束.

I think your original thought that use an interface (+ generic) was at the correct direction. In general you might want to add type constraints as well.

public interface ICustomValues {
  ....
}

public class MySpecificClass : ICustomValues {
  ....
}

public abstract class MyAbstract<T> where T : ICustomValues {
   public abstract T CustomValues {
     get;
     set;
   }
}


public class MyImplementation: MyAbstract<MySpecificClass>  {
  public override   MySpecificClass CustomValues { get; set; }
}

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