如何根据数组值计算空闲可用时间 [英] How to calculate free available time based on array values

问题描述

假设我有一个如下所示的数组:

Let say I have an array that looks like this:

{
    meeting: 'one',
    start_time: "07:15:00",
    end_time: "08:15:00"
},
{
    meeting: 'two',
    start_time: "15:45:00",
    end_time: "18:15:00"
}

现在我想计算我从 00:00:00 到 24:00:00 的所有空闲时间.

now i want to calculate all my free time availability from 00:00:00 to 24:00:00.

例如新数组将如下所示:

for example the new array will look like:

{
    meeting: 'free time',
    start_time: "00:00:00",
    end_time: "07:14:00"
},
{
    meeting: 'one',
    start_time: "07:15:00",
    end_time: "08:15:00"
},
{
    meeting: 'free time',
    start_time: "08:16:00",
    end_time: "15:44:00"
},
{
    meeting: 'two',
    start_time: "15:45:00",
    end_time: "18:15:00"
}

关于如何在没有插件的情况下完成这项工作的任何建议?

Any suggestion on how to get this done without a plugin?

推荐答案

您需要循环遍历数组，同时跟踪时间.jsFiddle

You need to loop through the arrays while keeping track of the times. jsFiddle

function subtractMinute(time){
  var h = +time.substr(0, 2);
  var m = +time.substr(3, 2);

  if(m > 0){
    m -= 1;
  }else{
    if(h > 0){
      h -= 1;
    }else{
      return false;
    }
    m = 59;
  }

  if(h < 10)
    h = '0'+h;

  if(m < 10)
    m = '0'+m;

  return h+':'+m+':00';
}

function addMinute(time){
  var h = +time.substr(0, 2);
  var m = +time.substr(3, 2);

  if(m < 59){
    m += 1;
  }else{
    if(h < 22){
      h += 1;
    }else{
      return false;
    }
    m = 0;
  }

  if(h < 10)
    h = '0'+h;

  if(m < 10)
    m = '0'+m;

  return h+':'+m+':00';
}

//If meetings is already sorted by time
//you can skip this next bit of code
meetings.sort(function(a, b){
  return a.start_time > b.start_time? 1: -1;
});

var schedule = [];
var start_time = '00:00:00';
var end_time = '23:59:00';
for(var i=0, l=meetings.length; i<l; i++){
  end_time = subtractMinute(meetings[i].start_time);

  if(i)
    start_time = addMinute(meetings[i-1].end_time);

  if((end_time && !i) || (end_time && i && meetings[i-1].end_time < meetings[i].start_time))
    schedule.push({meeting: 'free time', start_time: start_time, end_time: end_time});

  schedule.push(meetings[i]);

  if(i+1 === l){
    start_time = addMinute(meetings[i].end_time);

    if(start_time)
        schedule.push({meeting: 'free time', start_time: start_time, end_time: '23:59:00'});
  }
}

console.log(schedule);

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