如何在 Android 弹出菜单中设置默认选定选项? [英] How to set a default selected option in Android popup menu?

问题描述

我正在使用以下代码创建菜单:

I am using following code to create a menu:

    PopupMenu popup = new PopupMenu(getApplicationContext(), v);
    MenuInflater inflater = popup.getMenuInflater();
    inflater.inflate(R.menu.equalizer, popup.getMenu());
    popup.show();

均衡器.xml

<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android">
    <group android:checkableBehavior="single">
        <item android:id="@+id/flat"
              android:title="Flat" />
        <item android:id="@+id/stadium"
              android:title="Stadium" />
        <item android:id="@+id/jazz"
              android:title="Jazz" />
         <item android:id="@+id/rock"
              android:title="Rock" />
         <item android:id="@+id/pop"
              android:title="Pop" />
    </group>
</menu>

如何将菜单的第三个选项设置为默认选中?

How is it possible to set, let's say, 3rd option of the menu as selected by default?

我想以编程方式更改默认值.

I would like to change defaults programmatically.

推荐答案

已给出在 xml 中设置选中项的答案.如果你想在代码中做到这一点，请使用:

Answers have been given for setting a checked item in xml. If you want to do it in code, use:

popup.getMenu().getItem(2).setChecked(true);

选择第三项.在你当然膨胀了菜单之后......

to select the 3rd item. After you inflated the menu of course...

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