登录不适用于androip应用程序 [英] Login not working on androip app

问题描述

我正在 android studio 上构建一个需要注册和登录的应用程序，当我在登录时遇到问题时，我的注册工作正常，即使用户名和密码正确，我也会得到 false boolean 而不是 true，这是我的 PHP 文件:

Hi i'm building an app on android studio which requires register and login, My registration working fine while i'm having troubles with my login,I'm getting false boolean instead of true even if the username and password are correct, Here my PHP file:

`$con = mysqli_connect("localhost", "id1013905_trhtkv", "my password",` "id1013905_user");


    $username = $_POST["username"];
    $password = $_POST["password"];

    $statement = mysqli_prepare($con, "SELECT * FROM user WHERE username = ?");
    mysqli_stmt_bind_param($statement, "s", $username);
    mysqli_stmt_execute($statement);
    mysqli_stmt_store_result($statement);
    mysqli_stmt_bind_result($statement, $colUserID, $colName, $colUsername, $colAge, $colPassword);

    $response = array();
    $response["success"] = false;  

    while(mysqli_stmt_fetch($statement)){
        if (password_verify($password, $colPassword)) {
            $response["success"] = true;  
            $response["name"] = $colName;
            $response["age"] = $colAge;
        }
    }
    echo json_encode($response);
    ?> 

我的登录活动:

package com.ben.owner.say_something;

import android.app.AlertDialog;
import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;

import com.android.volley.RequestQueue;
import com.android.volley.Response;
import com.android.volley.toolbox.Volley;

import org.json.JSONException;
import org.json.JSONObject;

public class LoginActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.login_activity);

        final EditText etUsername = (EditText)findViewById(R.id.etUsername);
        final EditText etPassword = (EditText)findViewById(R.id.etPassword);
        final Button bLogin = (Button)findViewById(R.id.bLogin);
        final TextView registerLink = (TextView)findViewById(R.id.tvRegisterHere);

        registerLink.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                Intent registerIntent = new Intent(LoginActivity.this, RegisterActivity.class);
                LoginActivity.this.startActivity(registerIntent);
            }
        });

        bLogin.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                final String username = etUsername.getText().toString();
                final String password = etPassword.getText().toString();
                final Response.Listener<String>responseListener = new Response.Listener<String>() {
                    @Override
                    public void onResponse(String response) {
                        try {
                            JSONObject jsonResponse = new JSONObject(response);
                            boolean success = jsonResponse.getBoolean("success");
                            if (success){
                                String name = jsonResponse.getString("name");
                                int age = jsonResponse.getInt("age");
                                Intent intent = new Intent(LoginActivity.this, UserAreaActivity.class);
                                intent.putExtra("name",name);
                                intent.putExtra("username",username);
                                intent.putExtra("age",age);
                                LoginActivity.this.startActivity(intent);

                            }else{
                                AlertDialog.Builder builder = new AlertDialog.Builder(LoginActivity.this);
                                builder.setMessage("Login Failed")
                                        .setNegativeButton("Retry", null)
                                        .create()
                                        .show();

                            }
                        } catch (JSONException e) {
                            e.printStackTrace();
                        }

                    }
                };
                LoginRequest loginRequest = new LoginRequest(username,password,responseListener);
                RequestQueue queue = Volley.newRequestQueue(LoginActivity.this);
                queue.add(loginRequest);

            }
        });

    }
}

还有我的登录请求:

package com.ben.owner.say_something;

import com.android.volley.Request;
import com.android.volley.Response;
import com.android.volley.toolbox.StringRequest;

import java.util.HashMap;
import java.util.Map;

/**
 * Created by owner on 09/03/2017.
 */
public class LoginRequest extends StringRequest {
    private static final String LOGIN_REQUEST_URL = "https://saysomething.000webhostapp.com/Login.php";
    private Map<String, String> params;

    public LoginRequest(String username,String password, Response.Listener<String> listener){
        super(Request.Method.POST, LOGIN_REQUEST_URL, listener, null);
        params = new HashMap<>();
        params.put("username", username);
        params.put("password", password);

    }

    @Override
    public Map<String, String> getParams() {
        return params;
    }
}

推荐答案

为了找到你的错误，我只是建议在响应中检索服务器值.

To find your bug I just would suggest to retrieve server values in the responce.

我是说

代替

$response = array();
$response["success"] = false;  

while(mysqli_stmt_fetch($statement)){
    if (password_verify($password, $colPassword)) {
        $response["success"] = true;  
        $response["name"] = $colName;
        $response["age"] = $colAge;
    }
}
echo json_encode($response);

使用

    $response = array();
    $response["success"] = false;  
echo $statement;//or something like
    while(mysqli_stmt_fetch($statement)){

        if (password_verify($password, $colPassword)) {

echo $password;
echo $colPassword;
            $response["success"] = true;  
            $response["name"] = $colName;
            $response["age"] = $colAge;
        }
    }
    echo json_encode($response);

或调试您的服务器端.您的服务器代码似乎有误.

or debug your server side. It seems your server code is wrong.

检查这个例子

http://php.net/manual/en/mysqli-stmt.fetch.php

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