在 Angular2 的路由器中获取活动路由上的组件实例? [英] Get instance of component on active route in Angular2's router?

问题描述

我知道如果我调用 Router.routerState.snapshot，Angular2 中的 ActivatedRouteSnapshot.component 包含对激活路由的引用/类，但是如何获取组件类它的当前(或最小:创建的)实例?

I know that ActivatedRouteSnapshot.component in Angular2 contains the reference/class to the activated route if I call Router.routerState.snapshot but how to get for the component class the current (or minimal: one created) instance for it?

Injector.get(..) 不返回组件的实例，创建组件的新实例也无济于事(我).

Injector.get(..) does not return instances of components and creating a new instance of a component does also not help (me).

推荐答案

可以使用

<router-outlet
  (activate)='onActivate($event)'
  (deactivate)='onDeactivate($event)'></router-outlet>

其中 $event 是组件实例，例如将其分配给服务以使其在全球范围内可用.

where $event is the component instance and for example assign it to a service to make it available globally.

另见https://angular.io/api/router/RouterOutlet

您还可以创建一个自定义的 组件来自动执行此操作.

You can also create a custom <router-outlet> component that does that automatically.

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