没有 .subscribe 回调的 Angular http.post [英] Angular http.post without .subscribe callback

查看:39
本文介绍了没有 .subscribe 回调的 Angular http.post的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想知道我是否可以只发出一个 http post 请求而不订阅回调,像这样

I'm wondering if I can make just a http post request without subscribing on callbacks, something like this

 this._http.post('/list/items/update?itemId=' + itemId + "&done=" + done, null);

代替这个

 this._http.post('/list/items/update?itemId=' + itemId + "&done=" + done, null)
        .subscribe();

推荐答案

我不认为你可以.

http.post(以及 get、put、delete 等)返回一个冷 Observable,即一个 Observable:

http.post (and get, put, delete, etc) returns a cold Observable, i.e. an Observable for which:

在订阅期间创建并激活其底层生产者

its underlying producer is created and activated during subscription

来源.

这意味着 Observable 表示的函数只能通过 subscribe() 方法激活.

This means the function represented by the Observable is activated only with the subscribe() method.

便捷方法也订阅,查看Observable#toPromise()的实现细节此处.

Convenience methods subscribe too, see implementation details for Observable#toPromise() here.

这篇关于没有 .subscribe 回调的 Angular http.post的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆