在 Angular/Typescript 中用整数和字母对数组进行排序 [英] Sort an array with integers and letters alphabetic in Angular / Typescript

问题描述

我打算做什么

我尝试像这样对数组进行排序...

• 1
• 2
• 2(a)
• 2(b)
• 2(b) #AsimpleName
• 2(b) #NameWithN
• 3
• 4
• 4(a)
• ...

... 在 Angular2 中.

我当前的代码

组件

this.streetDetailRef = this.afDatabase.list('data/users/' + this.currentUserID + '/territory/' + this.sStreet.parentKey + '/' + this.sStreet.key + '/houseNumbers/');this.streetDetailData = this.streetDetailRef.snapshotChanges().map(changes => {return changes.map(c => ({ key: c.payload.key, ...c.payload.val() })).sort();});

我认为的循环

<strong>{{house.number }}</strong>...

'number' 在这种情况下是没有字母的干净数字.我将这封信存储在一个单独的 firebase 条目中.但如果需要，肯定可以将它们存储在同一个中.

附加信息:我正在使用 VadimDez 的 ngx-orderBy-pipe:

解决方案

这个函数应该可以解决问题:

function sortData(array: Array): Array{return array.sort((a, b) => a 

这里是使用示例:

const sorted = sortData(['4(a)', 4, 3, '2(b) #NameWithN', '2(b) #AsimpleName']);排序//[ '2(b) #AsimpleName', '2(b) #NameWithN', 3, 4, '4(a)' ]

What I plan to do

I try to sort an array like this...

• 1
• 2
• 2(a)
• 2(b)
• 2(b) #AsimpleName
• 2(b) #NameWithN
• 3
• 4
• 4(a)
• ...

... in Angular2.

My Current Code

Component

this.streetDetailRef = this.afDatabase.list('data/users/' + this.currentUserID + '/territory/' + this.sStreet.parentKey + '/' + this.sStreet.key + '/houseNumbers/');
this.streetDetailData = this.streetDetailRef.snapshotChanges().map(changes => {
  return changes.map(c => ({ key: c.payload.key, ...c.payload.val() })).sort();
});

The loop in my view

<ion-item-sliding *ngFor="let house of streetDetailData | async | orderBy: 'number':false" #slidingItem>
<strong>{{ house.number }}</strong> ...

'number' in this case is the clean number without letter. I store the letter in a separate firebase entry. But sure would be possible to store them in the same if needed.

Additional information: I'm using the ngx-orderBy-pipe by VadimDez: https://github.com/VadimDez/ngx-order-pipe

The current result

解决方案

This function should do the trick:

function sortData(array: Array<number | string>): Array<number | string> {
    return array.sort((a, b) => a < b ? -1 : 1);
}

And here is use example:

const sorted = sortData(['4(a)', 4, 3, '2(b) #NameWithN', '2(b) #AsimpleName']); 
sorted // [ '2(b) #AsimpleName', '2(b) #NameWithN', 3, 4, '4(a)' ]

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