按自定义顺序对对象数组进行排序 [英] Sort an object array by custom order

问题描述

我有一个对象数组，它们有一个名为CODE"的属性.

<预><代码>[{编号:168，NAME: "名字",代码:广告"},{编号:167，NAME: "第二名",代码:CC"},{编号:169，NAME: "第三名",代码:CCM"},{编号:170，NAME: "第四名",代码:CR"},]

如何按自定义顺序对数组进行排序，例如:

var item_order = ["CCM","CR","AD","CC"];

尝试了各种方法都没有成功.请帮忙.

解决方案

您可以将函数 sort 与函数 indexOf 一起使用.

var array = [ { ID: 168, NAME: "First name", CODE: "AD" }, { ID: 167, NAME:"第二名",CODE:"CC"},{ID:169,NAME:"第三名",CODE:"CCM"},{ID:170,NAME:"第四名",CODE:"CR"}],item_order = ["CCM","CR","AD","CC"];array.sort((a, b) => item_order.indexOf(a.CODE) - item_order.indexOf(b.CODE));console.log(array);

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I have an array of objects which have a property called 'CODE'.

[
  {
   ID: 168,
   NAME: "First name",
   CODE: "AD"
  },
  {
   ID: 167,
   NAME: "Second name",
   CODE: "CC"
  },
  {
   ID: 169,
   NAME: "Third name",
   CODE: "CCM"
  },
  {
   ID: 170,
   NAME: "Fourth name",
   CODE: "CR"
  },
]

How do I order the array by a customized order like:

var item_order = ["CCM","CR","AD","CC"];

Been trying various methods with no success. Please help.

解决方案

You can use the function sort along with the function indexOf.

var array = [  {   ID: 168,   NAME: "First name",   CODE: "AD"  },  {   ID: 167,   NAME: "Second name",   CODE: "CC"  },  {   ID: 169,   NAME: "Third name",   CODE: "CCM"  },  {   ID: 170,   NAME: "Fourth name",   CODE: "CR"  }],
    item_order = ["CCM","CR","AD","CC"];

array.sort((a, b) => item_order.indexOf(a.CODE) - item_order.indexOf(b.CODE));

console.log(array);

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