AngularJS:在原始数组中找到过滤值的索引位置 [英] AngularJS: find the index position of filtered value in the original array

问题描述

$scope.data = [{"name": "吉姆",身份证":25},{"name": "杰瑞",身份证":27},{"name": "丽思卡",身份证":20}];<div ng-repeat="person in data | filter: {id:20}">{{parent_index}}

parent_index - 实际数组中过滤元素的索引.

在这个例子中，parent_index 应该返回 2.如何找到它?

解决方案

在原数组中找到过滤值的索引位置

试试这个:

{{data.indexOf(person)}}

输出:2

演示 小提琴

$scope.data = [
    {
    "name": "Jim",
    "id" : 25
    },
    {
    "name": "Jerry",
    "id": 27
    },
    {
    "name": "Rithika",
    "id": 20
    }
    ];

    <div ng-repeat="person in data | filter: {id:20}">
        {{parent_index}}
    </div>

parent_index - Index of the filtered element in the actual array.

In this example, parent_index should return 2. how to find it?

解决方案

find the index position of filtered value in the original array

Try this one:

<div ng-repeat="person in data | filter: {id:20}">
    {{data.indexOf(person)}}
</div>

Output: 2

Demo Fiddle

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