子阵列上的角度 ng-repeat 过滤器 [英] Angular ng-repeat filter on subarray

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本文介绍了子阵列上的角度 ng-repeat 过滤器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

使用 Angular,我尝试在 FactorName 上使用 ng-repeat 过滤给定以下架构.
过滤使用<... ng-model="query.Factors.FactorName" ...> 不起作用(不足为奇).我还没有看到任何人试图以这种方式进行过滤的文献.

Angular 是否支持基于子数组元素属性的过滤?

<预><代码>[{"姓名":"1",因素":[{"FactorName":"FactorOne",类型":某种类型"},{"因子名称":"因子二",类型":某种类型"}]},{"姓名":"2",因素":[{"因子名称":"因子三",类型":某种类型"},{"因子名称":"因子四",类型":某种类型"}]}]

解决方案

还有另一个地方可以迭代数组,与 ng-repeat 一起工作,在带有自定义过滤器的双重绑定中.

工作演示

HTML

    <li>{{ x.Factors |因子过滤器 }}

JS

app.filter('factorFilter', function() {返回函数(项目){var 结果 = [];如果(项目){for (var i = 0; i < items.length; i++) {结果 = items[i]['FactorName'];}返回结果;} 别的 {返回 '​​Doh!';}}})

Using Angular, I'm trying to filter using ng-repeat on FactorName given the following schema.
Filtering using <... ng-model="query.Factors.FactorName" ...> doesn't work (not surprisingly). I haven't seen literature on anyone trying to filter in this way.

Does Angular support filtering based on a subarray element property ?

[
   {
      "Name":"1",
      "Factors":[
         {
            "FactorName":"FactorOne",
            "Type":"SomeType"
         },
         {
            "FactorName":"FactorTwo",
            "Type":"SomeType"
         }
      ]
   },
   {
      "Name":"2",
      "Factors":[
         {
            "FactorName":"FactorThree",
            "Type":"SomeType"
         },
         {
            "FactorName":"FactorFour",
            "Type":"SomeType"
         }
      ]
   }
]

解决方案

There is also another place where you can iterate on a array, working along side ng-repeat, in the double bindings with a custom filter.

Working Demo

HTML

<ul ng-repeat="x in factorData">
  <li>
    {{ x.Factors | factorFilter }}
  </li>
</ul>

JS

app.filter('factorFilter', function() {
    return function(items) {
        var results = [];
        if (items) {
            for (var i = 0; i < items.length; i++) {
                results = items[i]['FactorName'];
            }
            return results;
        } else {
          return 'Doh!';
        }
   }
})    

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