列式垫桌 [英] Column oriented mat-table

查看:18
本文介绍了列式垫桌的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一种情况,我从后端收到的数据是面向列的.该数据的示例如下:

<预><代码>[{ columnName: "ID", 单元格: [1, 2, 3, 4, 5] },{ columnName: "Name", 单元格: ["a", "b", "c", "d", "e"] }]

到目前为止,我已经设法像这样配置我的 mat-table:

<ng-container [matColumnDef]="column" *ngFor="let 列的显示列"><th mat-h​​eader-cell *matHeaderCellDef>{{column}} </th><td mat-cell *matCellDef="let element">{{element |json}}</td></ng-容器><tr mat-h​​eader-row *matHeaderRowDef="displayedColumns"></tr><tr mat-row *matRowDef="let row; columns:displayedColumns;"></tr>

这给了我以下结果:

而实际上我希望看​​到这样的表格:

|------|------||身份证 |姓名 ||------|------||1 |||2 |乙 ||3 || ||4 |d ||5 |电子 |

有什么方法可以调整 matRowDef 以便将单元格属性定义为行?理想情况下,我只想在 mat-table 中更改它,因此我不需要操作我的数据,然后再将其转换回来.

解决方案

您可以尝试根据需要修改现有响应:

HTML 代码:

<ng-container [matColumnDef]="column" *ngFor="let 列的显示列"><th mat-h​​eader-cell *matHeaderCellDef>{{column}} </th><td mat-cell *matCellDef="let element">{{元素[列]}} </td></ng-容器><tr mat-h​​eader-row *matHeaderRowDef="displayedColumns"></tr><tr mat-row *matRowDef="let row; columns:displayedColumns;"></tr>

TS 代码:

import { Component } from '@angular/core';从 '@angular/material' 导入 { MatTableDataSource };const ELEMENT_DATA: 任何[] = [{ columnName: "ID", 单元格: [1, 2, 3, 4, 5] },{ columnName: "Name", 单元格: ["a", "b", "c", "d", "e"] }];/*** @title`<table mat-table>`的基本使用*/@成分({选择器:'表基本示例',styleUrls: ['table-basic-example.css'],templateUrl: 'table-basic-example.html',})导出类 TableBasicExample {显示列 = []数据源 = 新的 MatTableDataSource([]);构造函数(){//动态获取列名ELEMENT_DATA.forEach(x => {this.displayedColumns.push(x.columnName)})//格式化你想要显示的数组让 newFormedArray = ELEMENT_DATA.reduce((array, { columnName, cells }) => {cell.forEach((cell, index) => {array[index] = Object.assign({ [columnName]: cell }, array[index])})返回数组;}, [])this.dataSource = new MatTableDataSource(newlyFormedArray);}}

StackBlitz

I have a situation where the data I receive from my backend is column-oriented. An example of how this data looks like is this:

[
    { columnName: "ID", cells: [1, 2, 3, 4, 5] },
    { columnName: "Name", cells: ["a", "b", "c", "d", "e"] }
]

So far I have managed to configure my mat-table like this:

<table mat-table [dataSource]="data" class="mat-elevation-z8">
    <ng-container [matColumnDef]="column" *ngFor="let column of displayedColumns">
        <th mat-header-cell *matHeaderCellDef> {{column}} </th>
        <td mat-cell *matCellDef="let element">{{element | json}}</td>
    </ng-container>

    <tr mat-header-row *matHeaderRowDef="displayedColumns"></tr>
    <tr mat-row *matRowDef="let row; columns: displayedColumns;"></tr>
</table>

which gives me the following result:

while in reality I'd like to see the table like this:

|------|------|
|  ID  | NAME |
|------|------|
|   1  |   a  |
|   2  |   b  |
|   3  |   c  |
|   4  |   d  |
|   5  |   e  |

Is there some way to adjust the matRowDef so it defines the cells property as rows? Ideally I would just like to change this in the mat-table, so I don't need to manipulate my data and later convert it back.

解决方案

You can try by modifying the existing response as per your need:

HTML Code:

<table mat-table [dataSource]="dataSource" class="mat-elevation-z8">

    <ng-container [matColumnDef]="column" *ngFor="let column of displayedColumns">
        <th mat-header-cell *matHeaderCellDef> {{column}} </th>
        <td mat-cell *matCellDef="let element"> {{element[column]}} </td>
    </ng-container>

    <tr mat-header-row *matHeaderRowDef="displayedColumns"></tr>
    <tr mat-row *matRowDef="let row; columns: displayedColumns;"></tr>
</table>

TS Code:

import { Component } from '@angular/core';

import { MatTableDataSource } from '@angular/material';

const ELEMENT_DATA: any[] = [
  { columnName: "ID", cells: [1, 2, 3, 4, 5] },
  { columnName: "Name", cells: ["a", "b", "c", "d", "e"] }
];

/**
 * @title Basic use of `<table mat-table>`
 */
@Component({
  selector: 'table-basic-example',
  styleUrls: ['table-basic-example.css'],
  templateUrl: 'table-basic-example.html',
})
export class TableBasicExample {
  displayedColumns = []
  dataSource = new MatTableDataSource([]);

  constructor() {
    // Take Column names dynamically
    ELEMENT_DATA.forEach(x => {
      this.displayedColumns.push(x.columnName)
    })

    // Format the array as you want to display
    let newlyFormedArray = ELEMENT_DATA.reduce((array, { columnName, cells }) => {
      cells.forEach((cell, index) => {
        array[index] = Object.assign({ [columnName]: cell }, array[index])
      })
      return array;
    }, [])
    this.dataSource = new MatTableDataSource(newlyFormedArray);
  }
}

StackBlitz

这篇关于列式垫桌的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆