如何根据 AngularJS 中的过滤结果更改类? [英] How to change class depending on filter result in AngularJS?

问题描述

我不知道如何根据过滤器的状态/结果更改类的样式.我的代码:

现在发生的是，样式列表"仍然存在，它有背景，因此即使过滤器中没有结果，背景仍然可见.

我希望我已经很好地解释了自己.

解决方案

您可以将过滤结果分配给一个中间变量，然后使用该变量有条件地应用您的类:

<div ng-class="{list:filteredItems.length}" style="margin-top: 30px;">

I cannot work out how to change the style of a class depending on the status/result of the filter. My code:

    <div data-ng-if="search.length >= 3" >
      <div data-ng-class="{list:true}" style="margin-top: 30px;">
       <a class="item item_recipe" data-ng-repeat="item in items | nonBlankFilter:search | filter:search" data-ng-click="$emit('search.click',item.PK);">
        <img class="thumbnail" src="images/thumbnails/{{item.THUMB}}">
        <div class="title">{{item.TITLE}}</div>
    </a>
</div>

What is happening now, is the style "list" is still there which has a background and thus the background is still visible, even when there is no results in the filter.

I hope I have explained myself well.

解决方案

You can assign your filter results to a intermediary variable and than use that variable to conditionally apply your class:

<div ng-if="search.length >= 3">
  <div ng-class="{list: filteredItems.length}" style="margin-top: 30px;">
    <a 
      class="item item_recipe" 
      ng-repeat="item in filteredItems = (items | nonBlankFilter:search | filter:search)" 
      ng-click="$emit('search.click',item.PK);"
    >
      <img class="thumbnail" src="images/thumbnails/{{item.THUMB}}">
      <div class="title">{{item.TITLE}}</div>
    </a>
  </div>
</div>

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