通过注解使用 Hibernate UUIDGenerator [英] Using Hibernate UUIDGenerator via annotations

问题描述

我使用我的 uuid 如下:

I'm using my uuid as following:

@Id
@GeneratedValue(generator = "uuid")
@GenericGenerator(name = "uuid", strategy = "uuid")
@Column(name = "uuid", unique = true)
private String uuid;

但我收到了一个智能的休眠警告:

but I'm getting a smart Hibernate warning:

使用org.hibernate.id.UUIDHexGenerator不生成 IETF RFC 4122合规的 UUID 值；考虑使用org.hibernate.id.UUIDGenerator 代替

Using org.hibernate.id.UUIDHexGenerator which does not generate IETF RFC 4122 compliant UUID values; consider using org.hibernate.id.UUIDGenerator instead

所以我想切换到 org.hibernate.id.UUIDGenerator，现在我的问题是我应该如何将它告诉 Hibernate 的生成器.我看到有人将它用作hibernate-uuid" - 所以这是我尝试过的，但结果是负面的:

So I want to switch to org.hibernate.id.UUIDGenerator, now my question is how should I tell it to Hibernate's generator. I saw some guy used it as a "hibernate-uuid" - so this is what I've tried, but with negative result:

@Id
@GeneratedValue(generator = "hibernate-uuid")
@GenericGenerator(name = "hibernate-uuid", strategy = "hibernate-uuid")
@Column(name = "uuid", unique = true)
private String uuid;

推荐答案

应该是uuid2:

...
@GenericGenerator(name = "uuid", strategy = "uuid2")
...

参见 5.1.2.2.1.各种额外的生成器.

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