如何检测在 MapView 中选择了哪个注释 [英] How can I detect which annotation was selected in MapView

问题描述

我在地图内做了一些注释，当我点击它们时，我会看到一些信息，我有一个按钮可以打开地图，如果我无法获取正确的信息，它应该可以绘制我的路线.

I've made a few annotations inside the Map and when I tap on them I see some informations and I have a button that opens Maps and with the right information that I can't take it should draw me my route.

这是我的代码:

我的 lat & 有 2 个双精度数组lon 我从查询中填写了它们.

I have 2 arrays of double for my lat & lon That I filled them from my query.

 var lat = [Double]()
 var lon = [Double]()

这些行用于填充注释

self.annot = Islands(title: object["name"] as! String, subtitle: object["address"] as! String,  coordinate: CLLocationCoordinate2D(latitude: (position?.latitude)!, longitude: (position?.longitude)!), info: object["address"] as! String)

self.map.addAnnotations([self.annot])

这是创建注释的地方:

func mapView(mapView: MKMapView, viewForAnnotation annotation: MKAnnotation) -> MKAnnotationView? {

    let identifier = "pin"

    if annotation.isKindOfClass(MKUserLocation) {
        return nil
    }

    let image = UIImage(named: "car")
    let button = UIButton(type: .Custom)
    button.frame = CGRectMake(0, 0, 30, 30)
    button.setImage(image, forState: .Normal)
    button.addTarget(self, action: #selector(Map.info(_:)), forControlEvents:UIControlEvents.TouchUpInside)

    var annotationView = mapView.dequeueReusableAnnotationViewWithIdentifier(identifier)
    if  annotationView == nil {
        annotationView = MKAnnotationView(annotation: annotation, reuseIdentifier: "pin")
        annotationView!.canShowCallout = true
        annotationView!.image = UIImage(named: "annotation")
        annotationView!.rightCalloutAccessoryView = button

    }
    else {
        annotationView!.annotation = annotation
    }

    return annotationView

}

最后这是按钮的功能，我应该在其中传递正确的信息(以及问题所在)

And finally this is the button's function where I should pass the right info ( and where the problem is)

   func info(sender: UIButton)
    {

        let latitute:CLLocationDegrees  =  lat[sender.tag]
        let longitute:CLLocationDegrees =  lon[sender.tag]

        let regionDistance:CLLocationDistance = 10000
        let coordinates = CLLocationCoordinate2DMake(latitute, longitute)
        let regionSpan = MKCoordinateRegionMakeWithDistance(coordinates, regionDistance, regionDistance)
        let options = [
            MKLaunchOptionsMapCenterKey: NSValue(MKCoordinate: regionSpan.center),
            MKLaunchOptionsMapSpanKey: NSValue(MKCoordinateSpan: regionSpan.span)
        ]
        let placemark = MKPlacemark(coordinate: coordinates, addressDictionary: nil)
        let mapItem = MKMapItem(placemark: placemark)
        mapItem.name = name[sender.tag]
        print(sender.tag)
        mapItem.openInMapsWithLaunchOptions(options)
    }

如您所见，我尝试使用发件人标签，但没有成功.

As you can see I tried with sender tag but with no luck.

我的自定义注释类

class Islands: NSObject, MKAnnotation {

    var title: String?
    var addr: String?
    var coordinate: CLLocationCoordinate2D
    var info: String?
    var subtitle: String?

    init(title: String, subtitle: String, coordinate: CLLocationCoordinate2D, info: String) {
        self.title = title 
        self.coordinate = coordinate
        self.info = info
        self.subtitle = subtitle

    }

}

推荐答案

为此，您可以使用 didSelectAnnotationView 中选定的 Annotation，然后将该注释存储到实例变量中，然后在您的 Button 操作方法中使用了注解.

For that you can use selected Annotation from didSelectAnnotationView, then store that annotation to instance variable and after that used annotation in your Button action method.

var selectedAnnotation: MKPointAnnotation?

func mapView(mapView: MKMapView, didSelectAnnotationView view: MKAnnotationView) {
    self.selectedAnnotation = view.annotation as? MKPointAnnotation
}

func info(sender: UIButton) {
    print(selectedAnnotation?.coordinate)
}

因为你有自定义 MKAnnotation 类，你需要使用它.

As of you have custom MKAnnotation class you need to use that.

var selectedAnnotation: Islands?

func mapView(mapView: MKMapView, didSelectAnnotationView view: MKAnnotationView) {
    self.selectedAnnotation = view.annotation as? Islands
}    

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