从匿名函数中打破 array_walk [英] Break array_walk from anonymous function

问题描述

有没有办法从匿名函数内部阻止 array_walk ?

Is there a way to stop an array_walk from inside the anonymous function ?

这是一些示例代码(有效)来说明我的意思，它检查数组是否只有数值.

Here is some sample code (that works) to show what I mean, that checks if an array has only numeric values.

$valid = true;
array_walk($parent, function ($value) use (&$valid) {
    if (!is_numeric($value)) {
        $valid = false;
    }
});

return $valid ? 'Valid' : 'Invalid';

如果我有一个足够大的数组，并且第一个条目无效，其余的(冗余)检查仍然完成，所以我想停止执行.

If I have a big enough array, and the first entry is invalid, the rest of the (redundant) checks are still done, so I would like to stop the execution.

使用 break/continue 不起作用(错误:致命错误:无法在 ... 中中断/继续 1 个级别).

Using break / continue doesn't work (error: Fatal error: Cannot break/continue 1 level in ...).

注意:我不想重写代码，我只想知道如果这是可能的.

Note: I don't want to rewrite the code, I just want to know IF this is possible.

推荐答案

如前所述，理论上可行，但我不建议这样做.以下是如何使用异常来突破 array_walk.

As stated, theoretically it's possible but I'd advise against it. Here's how to use an Exception to break out of the array_walk.

<?php
$isValid = false;

$array = range(1, 5);

try {
    array_walk($array, function($value) {
        $isAMagicNumber = 3 === $value;
        if ($isAMagicNumber) {
            throw new Exception;
        } 
    });
}catch(Exception $exception) {
    $isValid = true;
}

var_dump($isValid);

/*
    bool(true)
*/

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