如何为 mutate_each(和 summarise_each)使用匿名函数? [英] How to use anonymous functions for mutate_each (and summarise_each)?

问题描述

正如我们所知，可以在 R 中调用函数而不将它们分配给环境，例如

As we know, it is possible to call functions in R without assigning them to the environment, e.g.

> (function(x){x/2})(5)
[1] 2.5

我想在 mutate_each(或 summarise_each)调用中即时使用这些函数.例如，使用

I would like to use functions like these, on the fly, in a mutate_each (or summarise_each) call. For example, with

df <- data.frame(a = runif(10), b = rnorm(10))

我可能会尝试执行以下操作之一，但它们都返回错误:

I might attempt to do one of the following, but they all return errors:

library(dplyr)

> df %>%
+     mutate_each(funs((function(x){x/2})), a, b)
Error in eval(substitute(expr), envir, enclos) : 
  Unsupported type CLOSXP for column "a"
> 
> df %>%
+     mutate_each(list((function(x){x/2})), a, b)
Error: is.fun_list(calls) is not TRUE
> 
> 
> df %>%
+     mutate_each(funs((function(x){x/2})(.)), a, b)
Error in vapply(dots[missing_names], function(x) make_name(x$expr), character(1)) : 
  values must be length 1,
 but FUN(X[[1]]) result is length 2
> 

但是，如果我将功能分配给工作区，那么一切都会按预期进行:

However, if I assign the function to the workspace, then all works as expected:

tmp_fn <- function(x){x/2}

和

   > df %>%
+     mutate_each(funs(tmp_fn), a, b)
             a            b
1  0.360048105 -0.452285314
2  0.020175136  0.253063103
3  0.002351454 -0.148997643
4  0.262808493 -0.599555244
5  0.057246370  0.007567076
6  0.400027700  0.264901865
7  0.120505411 -0.346171709
8  0.266166200  0.116066231
9  0.031302148 -0.129739601
10 0.250212897  0.230194217

有没有办法在对mutate_each 或summarise_each 的调用中动态定义函数?

Is there a way to dynamically define functions in the call to mutate_each or summarise_each?

推荐答案

我们可以用括号把函数调用包裹起来

We can wrap the function call with parentheses

df %>%
     mutate_each(funs(((function(x){x/2})(.))))

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