如何使 Ansible 仅打印具有标准输出的任务 [英] How to make Ansible print only the task that has stdout

问题描述

我有一个包含多个任务的剧本.我需要 Ansible 只打印包含 STDOUT/debug 任务的任务

I have a playbook which contains multiple Tasks. I need Ansible to print only the Tasks which contains STDOUT /debug task

- hosts: "{{ v_host }}"
gather_facts: no
tasks:

- name: "Create /tmp in target in all VM's "
  file:
    path: /tmp
    state: directory
    owner: oracle
    group: oinstall
    mode: 0775

- copy:
    src: /xxx
    dest: /yyy
    owner: oracle
    group: oinstall
    force: yes
    mode: 0755

- name:  "Performing {{ patch_action }} of CPU patch on {{ v_host }} "
  shell: |
    cd /tmp
    sudo -u oracle ./patch.sh
  register: out
  
- debug: var=out.stdout_lines

我在没有 -v 选项的情况下执行剧本以获得更清晰的输出.输出如下所示.

I execute the playbook without -v option to have a cleaner output. The output looks like below.

ansible-playbook test.yml --extra-vars v_host=xyz.com.
    
TASK [Create /tmp in target in all VM's] ********************************************************************
ok: [ixyz.com]

TASK [copy] ********************************************************************
ok: [xyz.com]

TASK [Performing  of CPU patch on xyz.com] ***
changed: [xyz.com]

TASK [debug] *******************************************************************
ok: [xyz.com] => {
    "out.stdout_lines": [
        "Patch  123456     : applied on Tue Sep 29 10:11:58 GMT 2020", 
        "Patch description:  \"one-off\"", 
        "Patch  987654     : applied on Tue Sep 29 10:08:39 GMT 2020", 
        "Patch description:  \"One-off\"", 

    ]
}

当我执行剧本时是否有一个选项，它只为我提供 stdout/debug 的输出.我需要的唯一输出是

Is there an option when i execute the playbook, it gives me the output only for the stdout/debug . The only output that i need is

TASK [debug] *******************************************************************
ok: [xyz.com] => {
    "out.stdout_lines": [
        "Patch  123456     : applied on Tue Sep 29 10:11:58 GMT 2020", 
        "Patch description:  \"one-off\"", 
        "Patch  987654     : applied on Tue Sep 29 10:08:39 GMT 2020", 
        "Patch description:  \"One-off\"", 

    ]
}

推荐答案

可以使用回调 actionable 仅选择更改的任务.请参阅ansible-doc -t callback actionable"

It's possible to select only changed tasks by using the callback actionable. See "ansible-doc -t callback actionable"

"当您不关心 OK 或 Skipped 时使用此回调.此回调会抑制任何非失败"或已更改"状态."

例如下面的剧本

shell> cat pb.yml
- hosts: localhost
  tasks:
    - stat:
        path: /etc/passwd
      register: result
    - debug:
        var: result.stat.mode
    - debug:
        msg: test message
      changed_when: actionable|default(false)|bool

给予

shell> ansible-playbook pb.yml

PLAY [localhost] ****

TASK [stat] ****
ok: [localhost]

TASK [debug] ****
ok: [localhost] => {
    "result.stat.mode": "0644"
}

TASK [debug] ****
ok: [localhost] => {
    "msg": "test message"
}

PLAY RECAP ****
localhost: ok=3 changed=0 unreachable=0 failed=0 skipped=0 rescued=0 ignored=0

<小时>

actionable 回调将抑制输出.例如

---

The actionable callback will suppress the output. For example

shell> ANSIBLE_STDOUT_CALLBACK=actionable ansible-playbook pb.yml

PLAY [localhost] ****

PLAY RECAP ****
localhost: ok=3 changed=0 unreachable=0 failed=0 skipped=0 rescued=0 ignored=0

<小时>

您可以通过控制所选任务的已更改状态来启用其输出.例如

---

You can enable the output of the selected tasks by controlling their changed status. For example

shell> ANSIBLE_STDOUT_CALLBACK=actionable ansible-playbook pb.yml -e "actionable=true"

PLAY [localhost] ****

TASK [debug] ****
changed: [localhost] => {
    "msg": "test message"
}

PLAY RECAP ****
localhost: ok=3 changed=0 unreachable=0 failed=0 skipped=0 rescued=0 ignored=0

<小时>

问:如何使用默认"而不是可操作"来执行我的剧本?

A:下面的命令给出相同的结果

A: The command below gives the same results

shell> ANSIBLE_STDOUT_CALLBACK=default ANSIBLE_DISPLAY_SKIPPED_HOSTS=false ANSIBLE_DISPLAY_OK_HOSTS=false  ansible-playbook pb.yml -e "actionable=true"

这篇关于如何使 Ansible 仅打印具有标准输出的任务的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！