ansible - 从目录中删除非托管文件? [英] ansible - delete unmanaged files from directory?
问题描述
我想递归复制一个目录并将其中的所有 .j2 文件渲染为模板.为此,我目前使用以下几行:
- 模板:>src=/src/conf.d/{{ item }}dest=/dest/conf.d/{{ item|replace('.j2','') }}with_lines: find/src/conf.d/-type f -printf "%P\n"
现在我正在寻找一种方法来从此目录中删除非托管文件.例如,如果我从 /src/conf.d/
中删除文件/模板,我希望 Ansible 也从 /dest/conf.d/
中删除它.>
有没有办法做到这一点?我尝试摆弄 rsync --delete
,但我在模板中遇到了问题,这些模板的后缀 .j2
被删除了.
我会这样做,假设一个变量定义为 'managed_files' 顶部,它是一个列表.
- shell: ls -1/some/dir注册:内容- 文件:path=/some/dir/{{ item }} state=absentwith_items:contents.stdout_lines时间:项目不在 managed_files 中
I want to recursively copy over a directory and render all .j2 files in there as templates. For this I am currently using the following lines:
- template: >
src=/src/conf.d/{{ item }}
dest=/dest/conf.d/{{ item|replace('.j2','') }}
with_lines: find /src/conf.d/ -type f -printf "%P\n"
Now I'm looking for a way to remove unmanaged files from this directory. For example if I remove a file/template from /src/conf.d/
I want Ansible to remove it from /dest/conf.d/
as well.
Is there some way to do this? I tried fiddling around with rsync --delete
, but there I got a problem with the templates which get their suffix .j2
removed.
I'd do it like this, assuming a variable defined as 'managed_files' up top that is a list.
- shell: ls -1 /some/dir
register: contents
- file: path=/some/dir/{{ item }} state=absent
with_items: contents.stdout_lines
when: item not in managed_files
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