在 Ansible 的字典列表中搜索键 [英] Searching for key in a list of dicts in Ansible

问题描述

我有一个类似于以下内容的字典列表:

子网":[{"name": "subnet1-name34554",地址":192.168.1.100"id:"id1},{"name": "subnet2-name67678",地址":192.168.1.200"id":id2"},{"name": "subnet3-name23345",地址":192.168.1.300"id":id3"}]

我正在尝试使用部分名称搜索字典并返回全名.例如使用 subnet1 搜索应该返回 subnet1-name34554

如果我这样做:

- 名称:测试调试: msg="{{ 子网 | selectattr("name", "search", "subnet1") | list }}"

我得到一个带有单个 dict 的列表:

<预><代码> [{"name": "subnet1-name34554",地址":192.168.1.100"id:"id1}]

我不确定下一步只提取名称"键是什么，或者是否有更好的方法?

解决方案

结果你得到了 dicts 列表(单个 dict).

因此将其输入 first 过滤器以仅获取第一个元素，然后处理 name 属性.

- 名称:测试调试:msg: "{{ (subnets | selectattr('name', 'search', 'subnet1') | list | first).name }}"

I've got a list of dictionary that looks similar to the following:

"subnets": [
        {
            "name": "subnet1-name34554",
            "address": "192.168.1.100"
            "id: "id1"
        },
        {
            "name": "subnet2-name67678",
            "addr": "192.168.1.200"
            "id":   "id2"
        },
        {
            "name": "subnet3-name23345",
            "addr": "192.168.1.300"
            "id":   "id3"
        }
    ]

I'm trying to search the dicts with a partial name and return the full name. E.g searching with subnet1 should return subnet1-name34554

If I do something like:

- name: test
  debug: msg="{{ subnets |  selectattr("name", "search", "subnet1") | list  }}"

I get a list with a single dict back:

 [
   {
     "name": "subnet1-name34554",
     "address": "192.168.1.100"
     "id: "id1"
    }
 ]

I'm unsure what the next step to pull just the "name" key is, or if there is a better approach?

解决方案

You get list of dicts (single dict) as a result.

So feed it into first filter to get only first element and then address name property.

- name: test
  debug:
    msg: "{{ (subnets |  selectattr('name', 'search', 'subnet1') | list | first).name }}"

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