恢复使用 Copy 创建的备份文件 [英] restore backup file created with Copy

问题描述

如果备份文件是使用复制(使用备份=是)创建的，例如，使用此任务:

If a backup file is created using Copy (with backup=yes), for example, with this task:

 - name: copy file
      copy: 
        dest: path/to/dest
        src: path/to/src
        backup: yes

如果文件 path/to/dest 已经存在，它将被移动到一个类似于 path/to/dest.12345.2006-07-08@09:10:11 的文件中

If the file path/to/dest already exists, it will be moved in a file looking like path/to/dest.12345.2006-07-08@09:10:11

有没有办法恢复它，或者获取备份文件的文件名以便恢复它?

Is there a way to restore it, or to get the filename of the backup file in order to restore it ?

推荐答案

备份文件的绝对文件名(如果生成，那么如果changed"为真)，在输出对象中返回，所以(取以下为伪代码，因为我没有测试它):

The absolute file name of the backup file (if generated, so if "changed" is true), is returned in the output object, so (take the following as pseudocode as I am not testing it):

- name: copy file
  copy: 
     dest: path/to/dest
     src: path/to/src
     backup: yes
  register: copy_file

- debug: var=copy_file.backup_file

- name: restore backup
  copy:
     dest: path/to/dest
     src: copy_file.backup_file
     remote_src: true
  when: copy_file.changed and some condition of yours

参见:https://docs.ansible.com/ansible/latest/collections/ansible/builtin/copy_module.html#return-backup_file

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