Ant 1.8.0 版中记录的类路径、路径和路径元素在哪里? [英] Where are classpath, path and pathelement documented in Ant version 1.8.0?

问题描述

我正在查看 Apache Ant 1.8.0 版附带的文档，但找不到记录类路径、路径和路径元素的位置.我找到了一个页面，它描述了类似结构的路径，但它没有列出这些的有效属性或嵌套元素.我在文档中找不到的另一件事是描述文件列表、文件集、模式集和路径之间的关系以及如何来回转换它们.例如，必须有一种更简单的方法来仅编译一个包中的那些类，同时删除包类上的所有类依赖项并更新文档.

I'm looking over the documentation that comes with Apache Ant version 1.8.0 and can't find where classpath, path and pathelement are documented. I've found a page that describes path like structures but it doesn't list the valid attributes or nested elements for these. Another thing I can't find in the documentation is a description of the relationships between filelist, fileset, patternset and path and how to convert them back and forth. For instance there has to be an easier way to compile only those classes in one package while removing all class dependencies on the package classes and update documentation.

<!-- Get list of files in which we're interested. -->
<fileset id = "java.source.set"
    dir     = "${src}">
  <include name = "**/Package/*.java" />
</fileset>

<!-- Get a COMMA separated list of classes to compile. -->
<pathconvert property = "java.source.list"
    refid             = "java.source.set"
    pathsep           = ",">
  <globmapper from = "${src}/*.@{src.extent}"
      to           = "*.class" />
</pathconvert>

<!-- Remove ALL dependencies on package classes. -->
<depend srcdir = "${src}"
    destdir    = "${build}"
    includes   = "${java.source.list}"
    closure    = "yes" />

<!-- Get a list of up to date classes. -->
<fileset id = "class.uptodate.set"
    dir     = "${build}">
  <include name = "**/*.class" />
</fileset>

<!-- Get list of source files for up to date classes. -->
<pathconvert property = "java.uptodate.list"
    refid             = "class.uptodate.set"
    pathsep           = ",">
  <globmapper from="${build}/*.class" to="*.java" />
</pathconvert>

<!-- Compile only those classes in package that are not up to date. -->
<javac srcdir    = "${src}"
    destdir      = "${build}"
    classpathref = "compile.classpath"
    includes     = "${java.source.list}"
    excludes     = "${java.uptodate.list}"/>

<!-- Get list of directories of class files for package. --:
<pathconvert property = "class.dir.list"
    refid             = "java.source.set"
    pathsep           = ",">
  <globmapper from = "${src}/*.java"
      to           = "${build}*" />
</pathconvert>

<!-- Convert directory list to path. -->
<path id  = "class.dirs.path">
  <dirset dir  = "${build}"
      includes = "class.dir.list" />
</path>

<!-- Update package documentation. -->
<jdepend outputfile = "${docs}/jdepend-report.txt">
  <classpath refid = "compile.classpath" />
  <classpath location = "${build}" />
  <classespath>
    <path refid = "class.dirs.path" />
  </classespath>
  <exclude name = "java.*"  />
  <exclude name = "javax.*" />
</jdepend>

请注意，文件集、路径和逗号分隔列表之间有许多转换，只是为了获得不同 ant 任务所需的正确类型".有没有办法在复杂目录结构中处理最少文件的同时简化此操作?

Notice there's a number of conversions between filesets, paths and comma separated list just to get the proper 'type' required for the different ant tasks. Is there a way to simplify this while still processing the fewest files in a complex directory structure?

推荐答案

这是我能找到的最接近类路径文档的文档.

This is the closest I could find to documentation on classpath.

http://ant.apache.org/manual/using.html#path

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