Ant 和 XML 配置文件解析 [英] Ant and XML configuration file parsing

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本文介绍了Ant 和 XML 配置文件解析的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个如下形式的 XML 文件 -

I have an XML file of the following form -

<map MAP_XML_VERSION="1.0">
    <entry key="database.user" value="user1"/>
    ...
</map>

ant 是否具有读取此内容的本机能力并让我执行 xquery 以拉回键的值?通过 API 我没有看到这样的功能.

Does ant have a native ability to read this and let me perform an xquery to pull back values for keys? Going through the API I did not see such capabilities.

推荐答案

您可以使用 scriptdef 标记为您的类创建一个 JavaScript 包装器.在 JS 中,您几乎拥有 Java 的全部功能,并且可以执行您想要的任何类型的复杂 XML 解析.

You can use the scriptdef tag to create a JavaScript wrapper for your class. Inside JS, you pretty much have the full power of Java and can do any kind of complicated XML parsing you want.

例如:

<project default="build">        
    <target name="build">            
        <xpath-query query="//entry[@key='database.user']/@value"
                     xmlFile="test.xml" addproperty="value"/>
        <echo message="Value is ${value}"/>    
    </target>

    <scriptdef name="xpath-query" language="javascript">
        <attribute name="query"/>
        <attribute name="xmlfile"/>
        <attribute name="addproperty"/>

        <![CDATA[
            importClass(java.io.FileInputStream);
            importClass(javax.xml.xpath.XPath);
            importClass(javax.xml.xpath.XPathConstants);
            importClass(javax.xml.xpath.XPathFactory);
            importClass(org.xml.sax.InputSource);

            var exp = attributes.get("query");
            var filename = attributes.get("xmlfile");
            var input = new InputSource(new FileInputStream(filename));
            var xpath = XPathFactory.newInstance().newXPath();
            var value = xpath.evaluate(exp, input, XPathConstants.STRING);

            self.project.setProperty( attributes.get("addproperty"), value );

        ]]>

    </scriptdef>
</project>

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