Ant - 为所有子目录运行 Build.xml [英] Ant - Run a Build.xml for all subdirectories

问题描述

我有一个位于顶层的 build.xml，我希望脚本为每个子目录运行一个目标，并将子目录名称作为参数传递给 ANT 目标.

你能帮忙吗?/??

谢谢

解决方案

查看subant 任务.从该页面:

 <项目名称="subant" default="subant1"><property name="build.dir" value="subant.build"/><目标名称="subant1"><subant target=""><property name="build.dir" value="subant1.build"/><property name="not.overloaded" value="not.overloaded"/><文件集目录=."包括="*/build.xml"/></subant></目标></项目>

<块引用>

这个片段构建文件将在项目目录的每个子目录中运行 ant，其中可以找到一个名为 build.xml 的文件.在 subant 调用的 ant 项目中，属性 build.dir 的值为 subant1.build.

I have a build.xml sitting at the top level and I want the script to run a target for each subdirectory and pass in the subdirectory name as a parameter to the ANT target.

Can you help ?/??

Thanks

解决方案

Take a look at the subant task. From that page:

    <project name="subant" default="subant1">
        <property name="build.dir" value="subant.build"/>
        <target name="subant1">
            <subant target="">
                <property name="build.dir" value="subant1.build"/>
                <property name="not.overloaded" value="not.overloaded"/>
                <fileset dir="." includes="*/build.xml"/>
            </subant>
        </target>
    </project>

this snippet build file will run ant in each subdirectory of the project directory, where a file called build.xml can be found. The property build.dir will have the value subant1.build in the ant projects called by subant.

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