建立多个连接的 Android WebSocket 服务 [英] Android WebSocket Services making multiple connections

问题描述

我创建了一个 Web 套接字服务.但它一直在建立多个连接

I have created a Web Socket Service. but it keeping making multiple connection

我只希望该应用建立一个连接，除非网络连接断开然后再建立另一个.但是现在，如果我按下手机上的主页按钮，它会建立一个连接.并返回应用程序，它将建立另一个连接.

I just want the app to make one connection, unless the network connection drops then make another. But right now, it makes one connection, if I press the home button on the phone. and go back on the app, it will make another connection.

感谢你们的帮助.

onCreate... 我的 MainActivity

onCreate... of my MainActivity

Intent startServiceIntent = new Intent(this, WebSocketServices.class);
        startService(startServiceIntent);

清单

<!-- WebSocket -->
<receiver 
    android:name="com.example.basicplayerapp.core.NetworkReceiver">
   <intent-filter >
       <action android:name="android.net.conn.CONNECTIVITY_CHANGE" />
       <action android:name="android.intent.action.BOOT_COMPLETED" />
   </intent-filter> 
</receiver>
<service android:name="com.example.basicplayerapp.core.WebSocketServices"></service>

网络接收器

public class NetworkReceiver extends BroadcastReceiver {
    public static final String TAG = HomeActivity.class.getSimpleName();

    @Override
    public void onReceive(Context context, Intent intent) {         
        ConnectivityManager conn =  (ConnectivityManager)context.getSystemService(Context.CONNECTIVITY_SERVICE);
        NetworkInfo networkInfo = conn.getActiveNetworkInfo();

        if (networkInfo != null && networkInfo.getDetailedState() == NetworkInfo.DetailedState.CONNECTED) {
            Log.i(TAG, "connected");

            Intent startServiceIntent = new Intent(context, WebSocketServices.class);
            context.startService(startServiceIntent);

        } 
        else if(networkInfo != null){
            NetworkInfo.DetailedState state = networkInfo.getDetailedState();
            Log.i(TAG, state.name());
        }
        else {
            Log.i(TAG, "lost connection");

        }


    }//end onReceive    
};//end NetworkReceiver

Websocket 服务

public class WebSocketServices extends IntentService {
    public static final String TAG = WebSocketServices.class.getSimpleName();

    private static  String SOCKET_ADDR = "http://171.0.0.1:8080";
    private String message = null;
    private WebSocket socket = null;

    public WebSocketServices() {
        super("DownloadService");
    }


    @Override
    protected void onHandleIntent(Intent intent) {
        Log.i(TAG, "onHandleIntent");

        //SOCKET_ADDR = intent.getStringExtra("ip");

        if(socket==null || !socket.isOpen() || socket.isPaused())
        connectToPASocket(SOCKET_ADDR);

        Log.d(TAG,"Service Invoke Function");
    }//end onHandleIntent






    //=====================================================================================
    // Socket connection 
    //===================================================================================== 
    private void connectToPASocket(String SOCKET_ADDR) {
        Log.i(TAG, "connectToPASocket()");

        // Checking
        if (socket != null && socket.isOpen()) return;


        // Initiate web socket connection
        AsyncHttpClient.getDefaultInstance().websocket(SOCKET_ADDR, null,
                new AsyncHttpClient.WebSocketConnectCallback() {
                    @Override
                    public void onCompleted(Exception ex, WebSocket webSocket) {
                        Log.i(TAG, "onCompleted");

                        if (ex != null) {
                            Log.i(TAG, "onCompleted > if (ex != null)");
                            ex.printStackTrace();
                            return;
                        }

                        socket = webSocket;
                        socket.setStringCallback(new StringCallback() {
                            public void onStringAvailable(String s) {
                                Log.i(TAG, "socket.setStringCallback > onStringAvailable - s => " + s);

                                System.out.println("I got a string: " + s);
                                message = s;



                            }// end onStringAvailable
                        });// end socket.setStringCallback

                        socket.setDataCallback(new DataCallback() { // Find out what this does
                            @Override
                            public void onDataAvailable(DataEmitter emitter, ByteBufferList bb) {
                                Log.i(TAG, "socket.setDataCallback > onDataAvailable | emitter=> " + emitter + " | bb => " + bb);

                                System.out.println("I got some bytes!");
                                // note that this data has been read
                                bb.recycle();
                            }
                        });// end webSocket.setDataCallback

                    }// end onCompleted
                });// end AsyncHttpClient.getDefaultInstance()
    }// end connectToPASocket
}//end WebSocketServices

推荐答案

先生，我也遇到了类似的问题.

MrT, I had a similar probelm.

不要使用意图服务.只需使用服务.因为一旦intentService 完成，它就会自行完成.

Dont use intentService. Just use Service. Because once the intentService has been done, it will finish itself.

在您更改为 Service 后，您可以做的是使用 boolean 检查您的服务是否已启动，如下所示:

After you change to Service, What you can do, is to use boolean to check if your service has been started like so:

boolean isSockeStarted = false;



  @Override
  public int onStartCommand(Intent intent, int flags, int startId) {
...


        if (socket == null || !socket.isOpen() || socket.isPaused()) {

            if (isSockeStarted) { //not started
            } else {
                isSockeStarted = true;
            }
        }
....

也就是说，这个服务只会启动一次.直到你手动杀死它.

That mean, this service will only start once. until you kill it manually.

它对我有用，试着让我知道.

it worked for me, try and let me know.

这篇关于建立多个连接的 Android WebSocket 服务的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！