Flex4:如何在类中创建视图状态(代码隐藏) [英] Flex4: how to create the view states in as class (code-behind)

问题描述

根据 Adob​​e 的这份文档创建和应用视图状态 是 一个状态对象.如何在代码隐藏的 ActionScript 类中创建视图状态?

According to this document from Adobe Create and apply view states is <s:State/> a state object. How to create the view states in code-behind ActionScript class?

推荐答案

我找到了一个简单的解决方案，而且我不必使用蒙皮架构来声明状态.我什至没有在扩展 WindowedApplication 的 ApplicationClass 中声明状态.解决方案是:仅在 Main.MXML 中声明状态，并且一定要使用正确的命名空间，在我的情况下它应该是自定义".这是 Main.MXML:

I have found a simple solution, and I don't have to declare the states using skinning architecture. I don't even to declare the states in my ApplicationClass which extends WindowedApplication. The solution is: declare the states only in the Main.MXML and by all means with the right namespace, in my case it should be "custom". Here is the Main.MXML:

<?xml version="1.0" encoding="utf-8"?>
<custom:ApplicationClass xmlns:fx="http://ns.adobe.com/mxml/2009"
                         xmlns:s="library://ns.adobe.com/flex/spark"
                         xmlns:mx="library://ns.adobe.com/flex/mx"
                         xmlns:custom="components.*">
    <custom:states>  
        <s:State name="loginState"/> 
        <s:State name="infoState"/>
    </custom:states>

    <s:Panel id="loginPanel" title="Login" includeIn="loginState" />

</custom:ApplicationClass>

我只想在不同的面板之间切换，所以这个方法很适合我.当然还有其他情况，需要在蒙皮中声明状态.我从这个链接得到了这个解决方案:错误:无法解析为组件实现.

I only want to change between different Panels, so this method works well for me. There are certainly other cases, in which the states need to be declared in skinning. I have got this solution form this link: Error: Could not resolve to a component implementation.

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