当Visible属性设置为false使用JavaScript删除空 [英] Remove empty space when visible property is set to false using JavaScript
问题描述
我有一个DropDownList,当其选择的值发生变化(例如:0)我需要设置面板为True,另一个小组为False Visible属性的Visible属性。
。和选择其他值时,我需要做的,反之亦然使用Javascript。
目前,我正在实现这一目标,但空间保持原样。我怎样才能删除空格也。
谁能帮助我?
我附加了code也。
函数可见(VAL){ 变种的ddl =的document.getElementById(ddl_IDProof);
VAR selectedFilterType = drpFilterType.options [ddl.selectedIndex] .value的; 如果(selectedFilterType ==0){ 。的document.getElementById(pnl1)style.visibility =看得见;
。的document.getElementById(pnl2)style.visibility =隐藏;
} 其他{
。的document.getElementById(pnl1)style.visibility =隐藏;
。的document.getElementById(pnl2)style.visibility =看得见;
}
}
使用显示
而不是能见度
。
这将隐藏整个元素:
//显示pnl1(也许你不得不使用块的inline或inline-block的insdead)
。的document.getElementById(pnl1)的style.display =块;
//隐藏pnl2
。的document.getElementById(pnl2)的style.display =无;
I'm having a DropdownList and when its Selected Value is changed (for ex: 0 ) I need to set the visible property of a Panel to True and the visible property of another Panel to False.
and when another Value is selected I need to do Vice Versa Using JAVASCRIPT.
I'm currently achieving this but the space remains as it is. How can i remove the spaces also.
can anyone help me??
I'm attaching the code also.
function visible(val) {
var ddl = document.getElementById("ddl_IDProof");
var selectedFilterType = drpFilterType.options[ddl.selectedIndex].value;
if (selectedFilterType == "0") {
document.getElementById("pnl1").style.visibility = "visible";
document.getElementById("pnl2").style.visibility = "hidden";
}
else {
document.getElementById("pnl1").style.visibility = "hidden";
document.getElementById("pnl2").style.visibility = "visible";
}
}
Use display
instead of visibility
.
This will hide the entire element:
// Show pnl1 (maybe you have to use inline or inline-block insdead of block)
document.getElementById("pnl1").style.display = "block";
// Hide pnl2
document.getElementById("pnl2").style.display = "none";
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