Spark SQL 广播哈希连接 [英] Spark SQL broadcast hash join

问题描述

我正在尝试使用 SparkSQL 对数据帧执行广播哈希连接，如下所述:https://docs.cloud.databricks.com/docs/latest/databricks_guide/06%20Spark%20SQL%20%26%20DataFrames/05%20BroadcastHashJoin%20-%20scala.html

I'm trying to perform a broadcast hash join on dataframes using SparkSQL as documented here: https://docs.cloud.databricks.com/docs/latest/databricks_guide/06%20Spark%20SQL%20%26%20DataFrames/05%20BroadcastHashJoin%20-%20scala.html

在该示例中，(小)DataFrame 通过 saveAsTable 持久化，然后通过 spark SQL 进行连接(即通过 sqlContext.sql("..."))代码>

In that example, the (small) DataFrame is persisted via saveAsTable and then there's a join via spark SQL (i.e. via sqlContext.sql("..."))

我遇到的问题是我需要使用 sparkSQL API 来构建我的 SQL(我留下了大约 50 个带有 ID 列表的表，并且不想手动编写 SQL).

The problem I have is that I need to use the sparkSQL API to construct my SQL (I am left joining ~50 tables with an ID list, and don't want to write the SQL by hand).

How do I tell spark to use the broadcast hash join via the API?  The issue is that if I load the ID list (from the table persisted via `saveAsTable`) into a `DataFrame` to use in the join, it isn't clear to me if Spark can apply the broadcast hash join.

推荐答案

您可以明确地将 DataFrame 标记为足够小以进行广播使用 broadcast 功能:

You can explicitly mark the DataFrame as small enough for broadcasting using broadcast function:

Python:

from pyspark.sql.functions import broadcast

small_df = ...
large_df = ...

large_df.join(broadcast(small_df), ["foo"])

或广播提示(Spark >= 2.2):

or broadcast hint (Spark >= 2.2):

large_df.join(small_df.hint("broadcast"), ["foo"])

Scala:

import org.apache.spark.sql.functions.broadcast

val smallDF: DataFrame = ???
val largeDF: DataFrame = ???

largeDF.join(broadcast(smallDF), Seq("foo"))

或广播提示(Spark >= 2.2):

or broadcast hint (Spark >= 2.2):

largeDF.join(smallDF.hint("broadcast"), Seq("foo"))

SQL

您可以使用提示(Spark >= 2.2):

SELECT /*+ MAPJOIN(small) */ * 
FROM large JOIN small
ON large.foo = small.foo

或

SELECT /*+  BROADCASTJOIN(small) */ * 
FROM large JOIN small
ON large.foo = small.foo

或

SELECT /*+ BROADCAST(small) */ * 
FROM large JOIN small
ON larger.foo = small.foo

R (SparkR):

使用提示(Spark >= 2.2):

With hint (Spark >= 2.2):

join(large, hint(small, "broadcast"), large$foo == small$foo)

使用广播 (Spark >= 2.3)

With broadcast (Spark >= 2.3)

join(large, broadcast(small), large$foo == small$foo)

注意:

如果结构之一相对较小，则广播连接很有用.否则，它可能比完全洗牌要贵得多.

Broadcast join is useful if one of structures is relatively small. Otherwise it can be significantly more expensive than a full shuffle.

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