PySpark - 逐行转换为 JSON [英] PySpark - Convert to JSON row by row

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问题描述

我有一个非常大的 pyspark 数据框.我需要将数据帧转换为每一行的 JSON 格式的字符串,然后将该字符串发布到 Kafka 主题.我最初使用了以下代码.

I have a very large pyspark data frame. I need to convert the dataframe into a JSON formatted string for each row then publish the string to a Kafka topic. I originally used the following code.

for message in df.toJSON().collect():
        kafkaClient.send(message) 

然而,数据帧非常大,因此在尝试 collect() 时失败.

However the dataframe is very large so it fails when trying to collect().

我正在考虑使用 UDF 因为它会逐行处理它.

I was thinking of using a UDF since it processes it row by row.

from pyspark.sql.functions import udf, struct

def get_row(row):
    json = row.toJSON()
    kafkaClient.send(message) 
    return "Sent"

send_row_udf = F.udf(get_row, StringType())
df_json = df.withColumn("Sent", get_row(struct([df[x] for x in df.columns])))
df_json.select("Sent").show()

但是我收到一个错误,因为输入到函数的是列而不是行.

But I am getting an error because the column is inputed to the function and not the row.

出于说明目的,我们可以使用下面的 df,我们可以假设必须发送 Col1 和 Col2.

For illustrative purposes, we can use the df below where we can assume Col1 and Col2 must be send over.

df= spark.createDataFrame([("A", 1), ("B", 2), ("D", 3)],["Col1", "Col2"])

每一行的 JSON 字符串:

The JSON string for each row:

'{"Col1":"A","Col2":1}'
'{"Col1":"B","Col2":2}'
'{"Col1":"D","Col2":3}'

推荐答案

您不能像这样使用 select.使用 foreach/foreachPartition:

You cannot use select like this. Use foreach / foreachPartition:

import json

def send(part):
    kafkaClient = ...
    for r in part:
        kafkaClient.send(json.dumps(r.asDict()))

如果您需要诊断信息,只需使用 Accumulator.

If you need diagnostic information just use Accumulator.

在当前版本中,我会直接使用 Kafka 源(2.0 及更高版本):

In current releases I would use Kafka source directly (2.0 and later):

from pyspark.sql.functions import to_json, struct

(df.select(to_json(struct([df[x] for x in df.columns])).alias("value"))
    .write
    .format("kafka")
    .option("kafka.bootstrap.servers", bootstrap_servers)
    .option("topic", topic)
    .save())

例如,您将需要 Kafka SQL 包:

You'll need Kafka SQL package for example:

--packages org.apache.spark:spark-sql-kafka-0-10_2.11:2.2.1

这篇关于PySpark - 逐行转换为 JSON的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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