如何解析 JSON 对象 Android Studio [英] How to parse JSON Object Android Studio

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本文介绍了如何解析 JSON 对象 Android Studio的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

JSON 对象

{"Title":"Batman Returns","Year":"1992","Rated":"PG-13","Released":"19 Jun 1992","Runtime":"126 min","Genre":"Action","Director":"Tim Burton","Writer":"Bob Kane (Batman characters), Daniel Waters (story), Sam Hamm (story), Daniel Waters (screenplay)","Actors":"Michael Keaton, Danny DeVito, Michelle Pfeiffer, Christopher Walken","Language":"English","Country":"USA, UK","Awards":"Nominated for 2 Oscars. Another 2 wins & 15 nominations.","Poster":"http://ia.media-imdb.com/images/M/MV5BODM2OTc0Njg2OF5BMl5BanBnXkFtZTgwMDA4NjQxMTE@._V1_SX300.jpg","Metascore":"N/A","imdbRating":"7.0","imdbVotes":"199,878","imdbID":"tt0103776","Type":"movie","Response":"True"}

我正在尝试在 android studio 中解析这个对象,但是我收到一个错误:

I'm trying to parse this object in android studio however im getting an error:

of type org.json.JSONObject cannot be converted to JSONArray

这是我正在使用的代码

JSONArray mJsonArray = new JSONArray(jsonResult);
JSONObject movieObject = mJsonArray.getJSONObject(0);

String title = movieObject.getString("Title");

推荐答案

您的 json 包含一个对象,而不是一个数组.替换

Your json contains an object, not an array. Replace

JSONArray mJsonArray = new JSONArray(jsonResult);

JSONObject movieObject = new JSONObject(jsonResult);    
String title = movieObject.getString("Title");

这篇关于如何解析 JSON 对象 Android Studio的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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