ALM REST API v12.50 错误 401 [英] ALM REST API v12.50 error 401

查看:28
本文介绍了ALM REST API v12.50 错误 401的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

下午好,我正在开发一个需要使用 REST API 连接到 HPQC v12.50 的 C# 应用程序.我已经能够进行身份验证,然后我尝试重新使用我作为网络响应收到的 cookie 来执行查询.但是,我遇到了 401 错误,在阅读了多个论坛和 HP 关于 REST API 的文档后,我无法弄清楚我做错了什么.

Good afternoon, I am working on a C# application that needs to connect to HPQC v12.50 using the REST API. I have been able to authenticate and then I am trying to re-use the cookie I received as a webresponse to perform queries. However, I am stuck with an error 401 and after having read multiple forums and HP's doc about the REST API, I can't figure out what I am doing wrong.

这是我的代码块:

    public void LoginAlm(string StrServer, string StrUser, string StrPassword, string StrDomain, string StrProject)
    {
        //First, I am authenticating to the server (this works fine)
        string StrServerLogin = StrServer + "/authentication-point/authenticate";
        HttpWebRequest myWebRequest = (HttpWebRequest)WebRequest.Create(StrServerLogin);
        myWebRequest.Headers[HttpRequestHeader.Authorization] = "Basic " + Base64Encode(StrUser + ":" + StrPassword);
        WebResponse webResponse = myWebRequest.GetResponse();

        //Then, I am extracting the cookie from the header to re-use it for me subsequent requests.
        HttpWebRequest myWebRequest1 = (HttpWebRequest)WebRequest.Create(StrServer + "/rest/domains/"+StrDomain+"/projects/"+StrProject+"/defects&#1");
        string StrCookie = webResponse.Headers.ToString();
        StrCookie = StrCookie.Substring(StrCookie.IndexOf("Set-Cookie:") + 12);
        StrCookie = StrCookie.Substring(0, StrCookie.IndexOf("\r\n"));
        myWebRequest1.Headers[HttpRequestHeader.Cookie] = StrCookie;

        //Then, I am trying to perform my request, and the following line would always return an error 401.
        WebResponse webResponse1 = myWebRequest1.GetResponse();

        StreamReader reader = new StreamReader(webResponse1.GetResponseStream());
        textBox6.Text = reader.ReadToEnd();
    }

我在 HP 的文档中注意到的一件事是我应该收到一个令牌作为响应,但它似乎并不存在......

One thing I noticed in HP's doc is that I should be receiving a token as a response, but it does not seem to be there...

这是我第一次使用 REST API,如果它看起来微不足道,我很抱歉,但我已经浪费了太多时间!

It is my first experience with REST API and I am sorry if it seems trivial but I've wasted too much time on this already!

推荐答案

最后,我重新检查了 REST API 的文档,发现使用 ALM v12 的正确身份验证 URL 是/api/authentication/sign-in".50.

Finally, I rechecked the documentation of the REST API and found out the correct authentication URL to use is "/api/authentication/sign-in" with ALM v12.50.

它将在 webresponse 的标题中返回以下 cookie:- LWSSO_COOKIE_KEY- QCSession- ALM_USER- XSRF-令牌

It will return the following cookies in the header of the webresponse: - LWSSO_COOKIE_KEY - QCSession - ALM_USER - XSRF-TOKEN

这些 cookie 必须添加到您的下一个 web 请求中,位于 cookie 容器中.对于那些需要代码的人,这里是 C#:

These cookies have to be added to your next webrequest, in the cookie container. For those of you who would need the code, here it is in C#:

    public void LoginAlm(string StrServer, string StrUser, string StrPassword, string StrDomain, string StrProject)
    {
        //Creating the WebRequest with the URL and encoded authentication
        string StrServerLogin = StrServer + "/api/authentication/sign-in";
        HttpWebRequest myWebRequest = (HttpWebRequest)WebRequest.Create(StrServerLogin);
        myWebRequest.Headers[HttpRequestHeader.Authorization] = "Basic " + Base64Encode(StrUser + ":" + StrPassword);
        WebResponse webResponse = myWebRequest.GetResponse();

        //Once this is done, we create a new request, this example to get the information about defect #1 on a given project
        HttpWebRequest myWebRequest1 = (HttpWebRequest)WebRequest.Create(StrServer + "/rest/domains/"+StrDomain+"/projects/"+StrProject+"/defects/1");

        //Then, we create a cookie container to the webrequest where we will store the cookie that we've received from the authentication webresponse
        myWebRequest1.CookieContainer = new CookieContainer();
        Uri target = new Uri(StrServer);

        //We extract the LWSSO_COOKIE_KEY cookie and add it to the cookie container
        string StrCookie = webResponse.Headers.ToString();
        string StrCookie1 = StrCookie.Substring(StrCookie.IndexOf("LWSSO_COOKIE_KEY=") + 17);
        StrCookie1 = StrCookie1.Substring(0, StrCookie1.IndexOf(";"));
        myWebRequest1.CookieContainer.Add(new Cookie("LWSSO_COOKIE_KEY", StrCookie1) { Domain = target.Host });

        //Then the QCSession cookie
        string StrCookie2 = StrCookie.Substring(StrCookie.IndexOf("QCSession=") + 10);
        StrCookie2 = StrCookie2.Substring(0, StrCookie2.IndexOf(";"));
        myWebRequest1.CookieContainer.Add(new Cookie("QCSession", StrCookie2) { Domain = target.Host });

        //Then the ALM_USER cookie
        string StrCookie3 = StrCookie.Substring(StrCookie.IndexOf("ALM_USER=") + 9);
        StrCookie3 = StrCookie3.Substring(0, StrCookie3.IndexOf(";"));
        myWebRequest1.CookieContainer.Add(new Cookie("ALM_USER", StrCookie3) { Domain = target.Host });

        //And finally the XSRF-TOKEN cookie
        string StrCookie4 = StrCookie.Substring(StrCookie.IndexOf("XSRF-TOKEN=") + 12);
        StrCookie4 = StrCookie4.Substring(0, StrCookie4.IndexOf(";"));
        myWebRequest1.CookieContainer.Add(new Cookie("XSRF-TOKEN", StrCookie4) { Domain = target.Host });

        //We then send our webrequest and collect the webresponse
        WebResponse webResponse1 = myWebRequest1.GetResponse();
        StreamReader reader = new StreamReader(webResponse1.GetResponseStream());
    }

希望能帮到你!

这篇关于ALM REST API v12.50 错误 401的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆