如何使用python以字典等格式合并多个重复的键名 [英] How to merge multiple duplicate key names using python in a format like dictionary
问题描述
我有像字典这样格式的数据,其中数据有多个重复键,列表中的字符串作为值重复多次,我想合并所有具有相同名称及其值的键,数据发生在使用类似于字典的格式,但不是实际的字典,我将其称为字典仅仅是因为它的存在方式.
I had data in a format like dictionary where I the data had multiple duplicate keys repeated multiple times with strings in a list as values, I want to merge all the keys with the same name and their values, the data was happened to be in a format like dictionary but not an actual dictionary I am referring it as dictionary simply because of the way it was existed.
#Data 如下所示,
#Data I had looks like below,
"city":["New York", "Paris", "London"],
"country":["India", "France", "Italy"],
"city":["New Delhi", "Tokio", "Wuhan"],
"organisation":["ITC", "Google", "Facebook"],
"country":["Japan", "South Korea", "Germany"],
"organisation":["TATA", "Amazon", "Ford"]
我有 1000 个重复的键,其中包含一些重复且唯一的值,我想根据键合并或附加这些值.
I had 1000s of duplicate keys repeating with some repeated and unique values which I wanted merge or append based on key.
#预期输出
"city":["New York", "Paris", "London", "New Delhi", "Tokio", "Wuhan"],
"country":["India", "France", "Italy", "Japan", "South Korea", "Germany"],
"organisation":["ITC", "Google", "Facebook", "TATA", "Amazon", "Ford"],
任何人都可以提出建议.
Can anyone suggest.
推荐答案
- 已确定这不是dict,而是类似于 JSON 语法的 LR(1) 语法
- 采用这种方法使用 LR 解析器对其进行解析和标记
- https://lark-parser.readthedocs.io/en/latest/json_tutorial.html 展示了如何解析 JSON
- 需要一个小的调整,以便重复键工作(将dict视为列表,请参阅代码)
- 已使用 pandas 从解析器获取输出并根据需要重塑
- it's been established this is not a dict, it's a LR(1) grammar that is similar to a JSON grammar
- taking this approach parse and tokenise it with an LR parser
- https://lark-parser.readthedocs.io/en/latest/json_tutorial.html shows how to parse JSON
- needs a small adaptation so that duplicate keys work (consider a dict as a list, see code)
- have used pandas to take output from parser and reshape as you require
from lark import Transformer
from lark import Lark
import pandas as pd
json_parser = Lark(r"""
?value: dict
| list
| string
| SIGNED_NUMBER -> number
| "true" -> true
| "false" -> false
| "null" -> null
list : "[" [value ("," value)*] "]"
dict : "{" [pair ("," pair)*] "}"
pair : string ":" value
string : ESCAPED_STRING
%import common.ESCAPED_STRING
%import common.SIGNED_NUMBER
%import common.WS
%ignore WS
""", start='value')
class TreeToJson(Transformer):
def string(self, s):
(s,) = s
return s[1:-1]
def number(self, n):
(n,) = n
return float(n)
list = list
pair = tuple
dict = list # deal with issue of repeating keys...
null = lambda self, _: None
true = lambda self, _: True
false = lambda self, _: False
js = """{
"city":["New York", "Paris", "London"],
"country":["India", "France", "Italy"],
"city":["New Delhi", "Tokio", "Wuhan"],
"organisation":["ITC", "Google", "Facebook"],
"country":["Japan", "South Korea", "Germany"],
"organisation":["TATA", "Amazon", "Ford"]
}"""
tree = json_parser.parse(js)
pd.DataFrame(TreeToJson().transform(tree), columns=["key", "list"]).explode(
"list"
).groupby("key").agg({"list": lambda s: s.unique().tolist()}).to_dict()["list"]
输出
{'city': ['New York', 'Paris', 'London', 'New Delhi', 'Tokio', 'Wuhan'],
'country': ['India', 'France', 'Italy', 'Japan', 'South Korea', 'Germany'],
'organisation': ['ITC', 'Google', 'Facebook', 'TATA', 'Amazon', 'Ford']}
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