在 Java Applet 中调用 Web 服务方法 [英] Invoke web service method inside Java Applet

问题描述

我成功构建了一个简单的 Java Web 服务(例如您可以参考 "Building简单的网络服务" )

I succesfully builded a simple Java Web Service (as example you can refer to the "Building simple web service" )

在 Eclipse 中使用Java Web 服务代理技术"可以轻松创建 Web 服务客户端.教程中有说明.

In Eclipse is easy to create a web service client by using the "Java Web Service Proxy technique" indicated in the tutorial.

我想运行一个 Java Applet，它执行与 Java 客户端应用程序相同的操作:访问 Web 服务、调用方法并返回结果.

I want to run a Java Applet that do the same things of the java client application: access the web service, invoke the methods and return the results.

当我通过 Eclipse 运行代码时(右键单击>作为 Java Applet 运行......")一切正常......当我在一个简单的 html 页面中运行小程序时，小程序启动但陷入僵局:不抛出异常，进程被阻塞，在创建 MyWebServiceProxy 类的行上不做任何事情，调用默认构造函数.

When i run the code by Eclipse (right click > "run as Java Applet..") everything works fine.. when i run the applet in a simple html page the applet start but goes in deadlock: No exceptions are thrown, and the process is blocked without doing anything on the line that create the MyWebServiceProxy class, invoking the default constructor.

有人可以帮我吗?

我在这里粘贴了一些代码，让您更好地理解我在小程序中的操作:

I paste here some code to Let you understand better what i'm doing inside the applet:

public class SimpleWSApplet extends Applet {

 public void paint(Graphics g)
 {
  String msg = "Applet initialized";
  int i = 1;
  g.drawString(msg, 20, 20*i++);
  
  msg = "Error in applet";
  try {
   Service service = new Service();
   Call call = (Call)service.createCall();
   call.setTargetEndpointAddress("http://localhost:8080/AppletWSTest/services/SimpleWS");
   call.setOperationName(new QName("http://soapinterop.org/", "getMessage"));
   msg = (String)call.invoke(new Object[]{});
  } catch (Exception e) {
   e.printStackTrace();
   msg = "Error: "+e.getMessage();
  }
  g.drawString(msg, 20, 20*i++);
  //g.drawString(executeInvocation(msg), 20, 20*i++);
 }
}

显然我的网络服务被称为SimpleWS"；我调用的方法称为getMessage"，它不接受任何参数，并返回一个字符串.

Obviously my web service is called "SimpleWS" and the method that i invoke is called "getMessage", it takes no arguments, and returns a String.

请帮帮我..

推荐答案

如您所知，Java 小程序是在沙箱中执行的.默认情况下，applet 不能访问任何 web 资源，除了它们的原始服务器.只有经过签名的小程序才能访问此类资源.因此，您应该签署您的小程序.

As you know, java applets are executed in a sandbox. By default, applets don't have any access to any web resource except from their original servers. Only signed applets can access such kind of resources. Therefore, you should sign your applet.

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