从 JavaScript 调用时,签名的 Java Applet 会给出 AccessControlException [英] Signed Java Applet gives AccessControlException when calling from JavaScript

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本文介绍了从 JavaScript 调用时,签名的 Java Applet 会给出 AccessControlException的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

首先,我知道我的问题与 在这里.但是这个问题对我没有帮助.

First of all I'm aware that my question is same as in here. But that question did not helped me.

我有自签名小程序.

jarsigner -verify sJSApplet.jar
jar verified.

Warning:
This jar contains entries whose signer certificate will expire within six months.

Applet 的目的是从局域网机器打开 MS Word 文档.到目前为止,我已经尝试使用 Desktop.open()Runtime.exec() 打开.使用 AccessController.doPrivileged 和不使用.我总是收到 java.security.AccessControlException: access denied.

Applet's purpose is to open MS Word document from LAN machine. So far I've tried opening using Desktop.open() and Runtime.exec(). With AccessController.doPrivileged and without. I always get java.security.AccessControlException: access denied.

我别无选择.我还能做什么?

I'm out of options. What else I could do?

我无法使用 java.policy 文件.

I cannot use java.policy file.

HTML

<html>
    <head>
        <script>
            function openFile( command ) {
                    var applet = "<object type='application/x-java-applet' height='100' width='100' name='jsApplet'><param name='code' value='com.avacoda.swing.JSApplet'/><param name='archive' value='sJSApplet.jar' /><param name='mayscript' value='true'/><param name='filePath' value='C:\\note.txt'/>Applet failed to run.  No Java plug-in was found.</object>";

                    var body = document.getElementsByTagName("body")[0];
                    var div = document.createElement("div");
                    div.innerHTML = applet;
                    body.appendChild(div);
            }
        </script>
    </head>
    <body>
        <a href="#" onclick="openFile('C:/note.txt');">Open file</a>
    </body>
</html>

Java 代码:

public class WordApplet extends JApplet {

    @Override
    public void init() {
        openFile(getParameter("filePath"));
    };

    public void openFile(final String path) {
        AccessController.doPrivileged(new PrivilegedAction<Object>() {

            @Override
            public Object run() {
                try {
                        Runtime.getRuntime().exec("winword " + path); 
                        //Desktop.getDesktop().open(new File(path));
                } catch (Exception e) {
                    e.printStackTrace();
                }
                return null;
            }
        });
    }
}

完整的堆栈跟踪

java.security.AccessControlException: access denied (java.io.FilePermission <<ALL FILES>> execute)
    at java.security.AccessControlContext.checkPermission(Unknown Source)
    at java.security.AccessController.checkPermission(Unknown Source)
    at java.lang.SecurityManager.checkPermission(Unknown Source)
    at java.lang.SecurityManager.checkExec(Unknown Source)
    at java.lang.ProcessBuilder.start(Unknown Source)
    at java.lang.Runtime.exec(Unknown Source)
    at java.lang.Runtime.exec(Unknown Source)
    at java.lang.Runtime.exec(Unknown Source)
    at com.test.applet.JSApplet$1.run(JSApplet.java:34)
    at java.security.AccessController.doPrivileged(Native Method)
    at com.avacoda.swing.JSApplet.openFile(JSApplet.java:29)
    at com.avacoda.swing.JSApplet.init(JSApplet.java:25)
    at com.sun.deploy.uitoolkit.impl.awt.AWTAppletAdapter.init(Unknown Source)
    at sun.plugin2.applet.Plugin2Manager$AppletExecutionRunnable.run(Unknown Source)
    at java.lang.Thread.run(Unknown Source)
basic: Applet initialized

推荐答案

上面的代码示例没有任何问题.Desktop.getDesktop().open()Runtime.getRuntime().exec() 两种情况都可以完美运行.

There is nothing wrong with code samples above. Both cases Desktop.getDesktop().open() and Runtime.getRuntime().exec() works perfectly.

我的问题是 jar 包装不好.

My problem was badly packaged jar.

这篇关于从 JavaScript 调用时,签名的 Java Applet 会给出 AccessControlException的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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