在 Perl 中优雅地确定系统架构 [英] Elegantly Determining System Architecture Within Perl

问题描述

我正在寻找一种简单的方法来从 Perl 5 中确定系统是 32 位还是 64 位.我已经前后阅读了 perlvar 手册页，但没有发现一个包含系统 CPU 架构的变量(编译 Perl 的 CPU 架构将足够接近).这是我最近的一次:

I'm looking for a simple way to determine whether a system is 32- or 64-bit from within Perl 5. I have read the perlvar manual page backwards and forwards, and have not discovered a variable that contains the system's CPU architecture (the CPU architecture Perl was compiled for will come close enough). This is the closest I have come:

chomp (my $arch = `uname -m`);

我想知道是否有更优雅的方法来确定这一点；我讨厌依赖反引号表达式，因为它们都是瓶颈，往往不安全，并且经常(尤其是这个例子)破坏跨平台兼容性.Perl 没有理由不提供这些信息.

I was wondering if there was a more elegant way of determining this; I hate relying on backtick expressions, as they are both a bottleneck, tend to be insecure, and often (this example especially) break cross-platform compatibility. There is no reason Perl shouldn't already have this information available.

推荐答案

见Config 模块.

也许检查是否设置了 $Config{'archname64'} 就足够了.

Maybe checking whether $Config{'archname64'} is set would be sufficient.

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