跨通用函数隔离公共代码 [英] Isolate common code across generic functions

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本文介绍了跨通用函数隔离公共代码的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在一个类中有两个函数.唯一的区别是函数的参数(一个采用带有 X 的 Func,另一个采用 Y)和标有星号的行.

I have two functions in a class. The only differences are the parameter to the function (one taking a Func with a X and the other a Y) and the lines marked with asterisks.

有什么办法可以用星号隔离这两行或者有一个共同的函数,或者重写函数,使得try、catch块和最后几条语句只写一次?

Is there any way to isolate those two lines with asterisks or have a common function, or rewrite the functions such that the try, catch block and last few statements are written only once?

这里的目标是尽量减少代码重复.

The objective here is to minimize code duplication.

public T Do<T>(Func<X, T> something)
{
    try
    {
        var manager = CoreInfrastructure.GetManager(Prefix, Config.Param1, Config.Param2); //******
        if (manager != null) return something(manager);
        LoggingHandler.LogWarning(LogTitle, $"manager ({this}) is null.");
    }
    catch (MyException exp)
    {
        ExceptionHandler.HandleRecoverableException(exp, LogTitle,
            $"query on manager ({this}) failed.");
    }

    var msg = $"failed to query using manager ({this})!";
    LoggingHandler.LogCritical(LogTitle, msg);
    throw new MyException(msg);
}


public T Do<T>(Func<Y, T> something)
{
    try
    {
        var manager = CoreInfrastructure.GetManager(Prefix, Config.Param3); //******
        if (manager != null) return something(manager);
        LoggingHandler.LogWarning(LogTitle, $"manager ({this}) is null.");
    }
    catch (MyException exp)
    {
        ExceptionHandler.HandleRecoverableException(exp, LogTitle,
            $"query on manager ({this}) failed.");
    }

    var msg = $"failed to query using manager ({this})!";
    LoggingHandler.LogCritical(LogTitle, msg);
    throw new MyException(msg);
}

推荐答案

创建接受管理器和函数的泛型方法

Create generic method that accepts manager and function

    public T Do<T, TManager>(TManager manager, Func<TManager, T> something)
    {
        try
        {
            if (manager != null) return something(manager);
            LoggingHandler.LogWarning(LogTitle, $"manager ({this}) is null.");
        }
        catch (MyException exp)
        {
            ExceptionHandler.HandleRecoverableException(exp, LogTitle,
                $"query on manager ({this}) failed.");
        }

        var msg = $"failed to query using manager ({this})!";
        LoggingHandler.LogCritical(LogTitle, msg);
        throw new MyException(msg);
    }

    public void DoAll<T>(Func<X, T> somethingX, Func<Y, T> somethingY)
    {
        Do(CoreInfrastructure.GetManager(Prefix, Config.Param1, Config.Param2), somethingX);
        Do(CoreInfrastructure.GetManager(Prefix, Config.Param3), somethingY);
    }

正如 Damien_The_Unbeliever 提到的,如果创建管理器可以是 MyException 的来源,您可以添加 Func 而不是 TManager 管理器:

As Damien_The_Unbeliever mentioned if creating manager can be source of MyException you can add Func<TManager> instead of TManager manager:

    public T Do<T, TManager>(Func<TManager> managerCreate, Func<TManager, T> something)
    {
        try
        {
            TManager manager = managerCreate();
            if (manager != null) return something(manager);
            LoggingHandler.LogWarning(LogTitle, $"manager ({this}) is null.");
        }
        catch (MyException exp)
        {
            ExceptionHandler.HandleRecoverableException(exp, LogTitle,
                $"query on manager ({this}) failed.");
        }

        var msg = $"failed to query using manager ({this})!";
        LoggingHandler.LogCritical(LogTitle, msg);
        throw new MyException(msg);
    }

    public void DoAll<T>(Func<X, T> somethingX, Func<Y, T> somethingY)
    {
        Do(() => CoreInfrastructure.GetManager(Prefix, Config.Param1, Config.Param2), somethingX);
        Do(() => CoreInfrastructure.GetManager(Prefix, Config.Param3), somethingY);
    }

您可以更进一步,将 Func 替换为参数化函数,其中传递 PrefixConfig

You can go further and replace Func<TManager> with parametrized function where you pass Prefix and Config

这篇关于跨通用函数隔离公共代码的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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