使用 SDCard 上的一些文件创建一个 zip 文件 [英] Creating a zip file with some files on SDCard
问题描述
几天前我发布了一个问题,我意识到股票电子邮件应用程序无法在附件中发送多个文件:https://stackoverflow.com/questions/5773006/sending-email-with-multiple-attachement-fail-with-default-email-android-app-but
As I posted a question a few days ago, I realized thet the stock eMail app couldn't send multiple files in attachment: https://stackoverflow.com/questions/5773006/sending-email-with-multiple-attachement-fail-with-default-email-android-app-but
很遗憾,我没有得到答复,因此需要找到解决方法.
Unfortunately, I got no answer on it, so need to find a workaround.
用户必须在列表中选择一些 pdf 文件,然后使用股票应用程序通过电子邮件发送它们.由于多个附件失败,我将创建一个包含所有请求文件的 zip 文件并发送此唯一文件.
The user has to select in a list some pdf and send them by email with stock app. As the multiple attachment fail, I will create a zip file with all the requested files and sent this unique file.
那么,我可以用 SDCard 上的一些文件制作存档吗?
So, hoz can I make an archive with some files on SDCard?
我目前发现的是:http://developer.android.com/reference/java/util/zip/ZipFile.html
公共 ZipFile(文件文件)
public ZipFile (File file)
由于:API 级别 1 构造了一个新的带有指定文件的 ZipFile.
Since: API Level 1 Constructs a new ZipFile with the specified file.
但我不明白如何在多个文件中使用它.
But I don't understand how to use this with multiple files.
非常感谢,
推荐答案
我修改了 静态链接答案中的代码 到一个静态类中,但这对我很有用:
I modified the code from the static link answer into a static class, but this works great for me:
import android.util.Log;
import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class Zipper {
private static final int BUFFER = 2048;
public static void zip(String[] files, String zipFile) {
try {
BufferedInputStream origin = null;
FileOutputStream dest = new FileOutputStream(zipFile);
ZipOutputStream out = new ZipOutputStream(new BufferedOutputStream(dest));
byte data[] = new byte[BUFFER];
for (int i = 0; i < files.length; i++) {
Log.v("Compress", "Adding: " + files[i]);
FileInputStream fi = new FileInputStream(files[i]);
origin = new BufferedInputStream(fi, BUFFER);
ZipEntry entry = new ZipEntry(files[i].substring(files[i].lastIndexOf("/") + 1));
out.putNextEntry(entry);
int count;
while ((count = origin.read(data, 0, BUFFER)) != -1) {
out.write(data, 0, count);
}
origin.close();
}
out.finish();
out.close();
} catch (Exception e) {
e.printStackTrace();
}
}
}
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