如何将多个参数作为单个向量传递给函数? [英] How can I pass multiple arguments to a function as a single vector?

问题描述

我用六个参数创建了以下函数:

I created the following function with six args:

nDone <- function(under,strike,ttoe,vol,rf,dy) {
    pnorm(((log(under/strike)+ (rf-dy+(vol^2)/2)*ttoe)/(vol*(ttoe^0.5))))
}

nDone(90,100,3,0.17,0.05,0)
# Result: 
[1] 0.6174643

现在我在一个对象中创建一个具有相同值的向量，并尝试使用该向量调用该函数，但出现以下错误:

Now I create a vector with the same values in an object, and try to call the function using the vector, but get the following error:

d <- c(90,100,3,0.17,0.05,0)

nDone(d)

Error in under/strike : 'strike' is missing

我做错了什么以及如何解决?

What am I doing wrong and how to fix?

推荐答案

试试这个

 do.call(nDone, as.list(d))

<小时>

@joran 从评论中解释您第一次尝试时发生的情况:

---

Explanation of what's happening in your first attempt by @joran from the comments:

R 看到你传递一个参数给 nDone，即向量 d，它被传递给第一个函数参数，under>.由于您尚未为其他人指定默认值，因此它们丢失了，因此出现错误

R is seeing you pass a single argument to nDone, namely the vector d, which is handed off to the first function argument, under. Since you haven't specified a default value for the others, they are missing and hence the error

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