批处理脚本 - 遍历参数 [英] Batch-Script - Iterate through arguments

问题描述

我有一个带有多个参数的批处理脚本.我正在读取它们的总数，然后像这样运行 for 循环:

I have a batch-script with multiple arguments. I am reading the total count of them and then run a for loop like this:

@echo off
setlocal enabledelayedexpansion

set argCount=0
for %%x in (%*) do set /A argCount+=1
echo Number of processed arguments: %argCount%

set /a counter=0
for /l %%x in (1, 1, %argCount%) do (
set /a counter=!counter!+1 )

我现在想要做的是使用我的运行变量(x 或 counter)来访问输入参数.我在想类似这样的事情:

What I want to do now, is to use my running variable (x or counter) to access the input arguments. I am thinking aobut something like this:

REM Access to %1 
echo %(!counter!)

在理想的世界中，这一行应该打印出我的第一个命令行参数，但显然它没有.我知道我在使用 % 运算符时做错了什么，但是无论如何我可以像这样访问我的参数吗?

In an ideal world this line should print out my first command line argument but obviously it doesn't. I know I am doing something wrong with the % operator, but is there anyway I could access my arguments like this?

//edit: 澄清一下——问题是 %(!counter!) 为我提供了变量 counter 的值.counter=2 的含义它给了我 2 而不是 %2 的内容.

//edit: Just to make things clear - the problem is that %(!counter!) provides me with the value of the variable counter. Meaning for counter=2 it gives me 2 and not the content of %2.

推荐答案

这是访问第二个(例如)参数的一种方法(这可以放在 for/l 循环中，见下文.):

here's one way to access the second (e.g.) argument (this can be put in a for /l loop, see below.):

@echo off
setlocal enableDelayedExpansion
set /a counter=2
call echo %%!counter!
endlocal

所以:

setlocal enableDelayedExpansion
set /a counter=0
for /l %%x in (1, 1, %argCount%) do (
 set /a counter=!counter!+1
 call echo %%!counter! 
)
endlocal

这篇关于批处理脚本 - 遍历参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！