字符串... Java 中的参数 [英] String... parameter in Java
问题描述
我必须为家庭作业实现一个 API,而我的老师在 API 中的一个方法(基于 javadoc)中使用了我不熟悉的符号.
I have to implement an API for a homework assignment, and my instructor has used a notation I am unfamiliar with for one of the methods in the API (javadoc based).
public void method(String... strs);
..."是什么意思?后来看起来我需要使用单个字符串实参以及多个字符串实参来调用相同的方法...
What do the '...' mean? It later looks like I'll need to call this same method using a single string actual parameter, as well as multiple string actual parameters...
Java 没有可选参数(据我所知),所以我在这里有点困惑......
Java doesn't have optional arguments (to my knowledge), so I am a little confused here...
推荐答案
它叫做 varargs;http://docs.oracle.com/javase/6/docs/technotes/指南/语言/varargs.html
It's called varargs; http://docs.oracle.com/javase/6/docs/technotes/guides/language/varargs.html
这意味着您可以向该方法传递任意数量的参数(甚至为零).
It means you can pass an arbitrary number of arguments to the method (even zero).
在该方法中,参数将自动放入指定类型的数组中,您可以使用该数组访问各个参数.
In the method, the arguments will automatically be put in an array of the specified type, that you use to access the individual arguments.
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