将命令行参数传递给 python 脚本 [英] Pass command line argument to python script

问题描述

我有一个 file.py，我想在调用时将 base_url 传递给它，这样 base_url 变量值在运行 python file.py 时可以是动态的base_url='http://google.com' http://google.com 的值然后可以直接用于 file.py 的执行.

I have a file.py that I want to pass base_url to when called, so that base_url variable value can be dynamic upon running python file.py base_url='http://google.com' the value of http://google.com could then be used directly in the execution of file.py.

我该怎么做?

谢谢

推荐答案

命令行参数存储在列表 sys.argv 中.sys.argv[0] 是调用的命令的名称.

The command line arguments are stored in the list sys.argv. sys.argv[0] is the name of the command that was invoked.

import sys

if len(sys.argv) != 2:
    sys.stderr.write("usage: {} base_url".format(sys.argv[0]))
    exit(-1) # or deal with this case in another way
base_url_arg = sys.argv[1]

根据输入格式，base_url_arg 可能需要进一步处理.

Depending on the input format, base_url_arg might have to be further processed.

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