如何让 runuser 正确转发所有命令行参数，而不是试图解释它们? [英] How to make runuser correctly forward all command line arguments, instead of trying to interpret them?

问题描述

我得到了这个简单的脚本:

I got this simple script:

#!/bin/bash
SOURCE_USER=$USER
DESTINE_USER=$1

id -u $SOURCE_USER > /dev/null 2>&1

if [ "$?" == "1" ] || [ -z $SOURCE_USER ]
then
    printf "Error: Invalid source user '$SOURCE_USER'\\n"
    exit 1
fi

if [ -z $DESTINE_USER ]
then
    printf "Error: Invalid destine user '$DESTINE_USER'\\n"
    exit 1
fi

SOURCE_GROUPS=$(id -Gn ${SOURCE_USER} | sed "s/${SOURCE_USER} //g" | sed "s/ ${SOURCE_USER}//g" | sed "s/ /,/g")
SOURCE_SHELL=$(awk -F : -v name=${SOURCE_USER} '(name == $1) { print $7 }' /etc/passwd)

id -u $DESTINE_USER > /dev/null 2>&1

if [ "$?" == "1" ]
then
    printf "Creating destine user %s\\n" "$DESTINE_USER"
    useradd --groups ${SOURCE_GROUPS} --shell ${SOURCE_SHELL} --create-home ${DESTINE_USER}
    passwd ${DESTINE_USER}
    xhost '+si:localuser:$DESTINE_USER'
    sudo usermod -G "$SOURCE_USER" "$DESTINE_USER"
else
    printf "Updating destine user '%s' with groups '%s' and shell '%s'\\n" "$DESTINE_USER" "$SOURCE_GROUPS" "$SOURCE_SHELL"
    sudo usermod -a -G "$SOURCE_GROUPS" "$DESTINE_USER"
    sudo chsh -s "$SOURCE_SHELL" "$SOURCE_USER"
fi

sudo runuser sublime_vanilla -c "${@:2}"

我是这样运行的:

$ bash run_as_user.sh sublime_vanilla /usr/bin/subl -n "./New Empty File"

但是当我运行它时，我得到了这个错误:

But when I run it, I got this error:

runuser: invalid option -- 'n'
Try 'runuser --help' for more information.

但是如果我将 sudo runuser sublime_vanilla -c "${@:2}" 替换为 sudo runuser sublime_vanilla -c "\"$2\" \"$3\" \"$4\" \"$5\" \"$6\" \"$7\" \"$8\" \"${@:9}\""

But if I replace sudo runuser sublime_vanilla -c "${@:2}" with sudo runuser sublime_vanilla -c "\"$2\" \"$3\" \"$4\" \"$5\" \"$6\" \"$7\" \"$8\" \"${@:9}\""

然后，Sublime Text 在新窗口中正确打开文件 "./New Empty File".

Then, Sublime Text correctly opens the file "./New Empty File" in a new window.

如何使 runuser 正确理解所有带有可变数量命令行参数的参数，即无需硬编码 "\"$2\" \"$3\" \"$4\..."?

How to make runuser correctly understand all argument with a variable number of command line arguments, i.e., without hard coding "\"$2\" \"$3\" \"$4\" ..."?

推荐答案

这与您的上一个问题略有不同，因为对于 -c 选项，您必须将参数扩展为单个字符串.

This is slightly different from your last question because you have to make the expansion of the arguments into a single string for the -c option.

bash printf 格式化程序 %q 是你的朋友在这里:

The bash printf formatter %q is your friend here:

cmd=$( printf '%q ' "${@:2}" )
sudo runuser sublime_vanilla -c "$cmd"

另一方面，快速阅读 runuser 手册页建议:

On the other hand, a quick perusal through the runuser man page suggests:

sudo runuser -u sublime_vanilla "${@:2}"

<小时>

另一个想法:sudo runuser -u sublime_vanilla -- "${@:2}" 用双连字符表示 runuser 选项的结束.

---

Another thought: sudo runuser -u sublime_vanilla -- "${@:2}" with the double hyphens to indicate the end of the runuser options.

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