龙卷风发布请求:缺少参数 [英] tornado post request: missing argument
问题描述
我正在使用 Tornado 构建一个 Web 服务器，现在我正在创建一个登录模块.这是代码:
<form id="uploadForm"><div class="form-group"><label for="exampleInputEmail1">电子邮件地址</label><input name="name" type="email" class="form-control" id="exampleInputEmail1" placeholder="Email"><div class="form-group"><label for="exampleInputPassword1">密码</label><input name="password" type="password" class="form-control" id="exampleInputPassword1" placeholder="密码">
<button id="submit" type="button" class="btn btn-default">提交</button></表单><script src="../js/plugins/jquery-3.2.1.min.js?v=c9f5aeeca3"></script><script src="../js/common/bootstrap.min.js?v=5869c96cc8"></script><脚本>$(函数(){$('#submit').on('click',function(){$.ajax({url: 'http://www.example.com/login',方法:'POST'，数据:$('#uploadForm').serialize(),内容类型:假，过程数据:假，缓存:假，成功:功能(数据){控制台日志(数据)；if( 数据 === '错误'){alert('登录失败')}别的{location.href = 数据；}},错误:函数(jqXHR){警报('错误')；}});});});
以及后端部分:
class LoginHandler(tornado.web.RequestHandler):def post(self, path):尝试:打印(self.request.body)name = self.get_body_argument("name")除了作为 e 的例外:打印(e)当我做测试时，我可以看到 print(self.request.body) 给了我结果:b'name=test&password=tttt'但在那之后我得到了一个例外:
HTTP 400:错误请求(缺少参数名称)
name=test 只是在 http 正文中，但为什么它告诉我缺少参数名称?
Tornado 仅支持application/x-www-form-urlencoded"和multipart/form-data"作为内容类型.所以当我们向服务器发送 post 请求时，我们必须使用正确的 contentType 发送请求.例如，
$.ajax({url: 'http://www.example.com/login',方法:'POST'，数据:$('#uploadForm').serialize(),contentType: 'application/x-www-form-urlencoded',过程数据:假，...另外，我们可以忽略ajax中的contentType，因为'application/x-www-form-urlencoded'是默认设置的.
I'm using tornado to build a web server and now I'm creating a login module. Here is the code:
<body>
<form id="uploadForm">
<div class="form-group">
<label for="exampleInputEmail1">Email address</label>
<input name="name" type="email" class="form-control" id="exampleInputEmail1" placeholder="Email">
</div>
<div class="form-group">
<label for="exampleInputPassword1">Password</label>
<input name="password" type="password" class="form-control" id="exampleInputPassword1" placeholder="Password">
</div>
<button id="submit" type="button" class="btn btn-default">Submit</button>
</form>
</body>
<script src="../js/plugins/jquery-3.2.1.min.js?v=c9f5aeeca3"></script>
<script src="../js/common/bootstrap.min.js?v=5869c96cc8"></script>
<script>
$(function(){
$('#submit').on('click',function(){
$.ajax({
url: 'http://www.example.com/login',
method: 'POST',
data: $('#uploadForm').serialize(),
contentType: false,
processData: false,
cache: false,
success: function(data) {
console.log(data);
if( data === 'ERROR'){
alert('login failed')
}else{
location.href = data;
}
},
error: function (jqXHR) {
alert('ERROR');
}
});
});
});
</script>
And the backend part:
class LoginHandler(tornado.web.RequestHandler):
def post(self, path):
try:
print(self.request.body)
name = self.get_body_argument("name")
except Exception as e:
print(e)
When I do a test, I can see that print(self.request.body) gives me the result: b'name=test&password=tttt' but after that I get an exception:
HTTP 400: Bad Request (Missing argument name)
name=test is just in the http body but why it tells me missing argument name?
Tornado only supports "application/x-www-form-urlencoded" and "multipart/form-data" as content type. So when we send a post request to the server, we must send the request with the right contentType. For example,
$.ajax({
url: 'http://www.example.com/login',
method: 'POST',
data: $('#uploadForm').serialize(),
contentType: 'application/x-www-form-urlencoded',
processData: false,
...
Also, we can neglect the contentType in ajax as 'application/x-www-form-urlencoded' is set by default.
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