将可选参数传递给 r 中的函数 [英] Passing in optional arguments to function in r

问题描述

如何将可选参数传递给 R 中的函数?

How do I pass in optional arguments to a function in R?

这方面的一个例子是，我可能希望从模型的特定超参数组合中创建一个函数.但是，我不想配置所有超参数，因为在大多数情况下许多超参数都不相关.

An example of this is I might want to be make a function out of a certain combination of hyperparameters for a model. However, I don't want to configure ALL of the hyperparameters as many aren't relevant in most scenarios.

有时我希望能够手动传入我想更改的一个超参数.我经常在函数中看到 ...，但无法弄清楚这是否与这种情况有关，或者至少如何使用它们.

From time to time I would like to be able to manually pass in that one hyper-parameter I'd like to change. I often see the ... in functions, but can't figure out if that is relevant to this situation or at least how to use them.

library(gbm)
library(ggplot)
data('diamonds', package = 'ggplot2')

 example_function = function(n.trees = 5){
      model=gbm(formula = price~ ., n.trees = 5, data = diamonds)
}  


# example of me passing in an unplanned argument
example_function(n.trees = 5, shrinkage = 0.02)

这是否可以以智能方式处理?

Is this possible to handle in an intelligent way?

推荐答案

您可以使用 ... 参数(记录在 ?dots 中)从一个调用函数.在你的情况下，试试这个:

You can use the ... argument (documented in ?dots) to pass down arguments from a calling function. In your case, try this:

library(gbm)
library(ggplot2)
data('diamonds', package = 'ggplot2')

example_function <- function(n.trees = 5, ...){
     gbm(formula = price~ ., n.trees = 5, data = diamonds, ...)
}  


# Pass in the additional 'shrinkage' argument 
example_function(n.trees = 5, shrinkage = 0.02)
## Distribution not specified, assuming gaussian 
## gbm(formula = price ~ ., data = diamonds, n.trees = 5, shrinkage = 0.02)
## A gradient boosted model with gaussian loss function.
## 5 iterations were performed.
There were 9 predictors of which 2 had non-zero influence.

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