在ASP.NET MVC形式张贴到另一个模型 [英] Posting to another model from a form in ASP.NET MVC

问题描述

如果我有了一个模型的视图，可以说汽车。

If I have a view that has a model, lets say Car..

@model Project.Car

这视图内我要创建将数据发送到一个新的模式形式

inside that view I want to create a form that sends data to a new model

    @using (Html.BeginForm("Add", "Controller"))
    {
        @Html.Hidden("ID", "1")
        @Html.Hidden("UserID", "44")
        @Html.TextArea("Description")
    }

我发现，如果我的行为与我的定义视图模型它不工作（型号总是空）：

I've noticed that if my action is defined with my ViewModel it does not work (model is always null):

    [HttpPost]
    public PartialViewResult Add(ViewModels.NewModel model)

不过，如果我使用它的工作原理的FormCollection：

However, if I use a FormCollection it works:

    [HttpPost]
    public PartialViewResult Add(FormCollection formCollection)

下面是视图模型：

public class NewModel
{
    public int ID { get; set; }
    public int UserID { get; set; }
    public string Description { get; set; }
}

我的问题是，我可以从我的表单POST数据newModel，并向来？它坐落在观是正确的绑Project.Car。它是一种小型化，需要上传一组不同的数据有无关Project.Car在页面上。

My question is can I post data to NewModel from my form? The View that it sits on is correct to be tied to Project.Car. Its a small form on the page that needs to post a different set of data that has nothing to do with Project.Car.

推荐答案

您有您的模型和动作名称之间有差异。在这个例子中，你表现出的模式被称为添加而在你的行动，你正在使用 ViewModels.NewModel 。更糟的是，你的看法是强类型到一个名为车模式。凌乱的这一切。

You have a discrepancy between the name of your model and your action. In the example you have shown the model is called Add whereas in your action you are using ViewModels.NewModel. Even worse, your view is strongly typed to a model called Car. Messy all this.

因此​​，通过定义一个正确的视图模型启动：

So start by defining a correct view model:

public class CarViewModel
{
    public int ID { get; set; }
    public int UserID { get; set; }
    public string Description { get; set; }
}

然后控制器：

public class CarsController: Controller
{
    public ActionResult Add()
    {
        var model = new CarViewModel
        {
            // don't ask me, those are the values you hardcoded in your view
            ID = 1,
            UserID = 44,
        };
        return View(model);
    }   

    [HttpPost]
    public PartialViewResult Add(CarViewModel model)
    {
        ...
    }
}

和相应的强类型以便您的视图模型：

and a corresponding strongly typed view to your view model:

@model CarViewModel
@using (Html.BeginForm())
{
    @Html.HiddenFor(x => x.ID)
    @Html.HiddenFor(x => x.UserID)
    @Html.TextAreaFor(x => x.Description)
    <button type="submit">Add</button>
}

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