如何在 Java 中将两个数组映射到一个 HashMap? [英] How to map two arrays to one HashMap in Java?

查看:40
本文介绍了如何在 Java 中将两个数组映射到一个 HashMap?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有两个字符串数组.一种简称.

I have two String arrays. One having short name.

// days short name
String[] shortNames = {"SUN", "MON", "...", "SAT"};

另一个名字很长.

// days long name
String[] longNames = {"SUNDAY", "MONDAY", "....", "SATURDAY"};

两者都具有相同数量的元素.如何在 HashMap 中将短名称映射为 KEY,将长名称映射为 VALUE?

Both having same number of elements. How can I map short name as KEY and long name as VALUE in HashMap?

HashMap<String, String> days = new HashMap<>();

我知道,我可以通过循环来制作.有没有更好的办法?

I know, I can make by looping. Is there a better way?

推荐答案

有很多方法可以做到这一点.一个相当容易理解和应用的方法是使用 Java 8 流和收集器从索引流映射到键值对:

There are lots of ways you can do this. One that is fairly easy to understand and apply is using Java 8 streams and collectors to map from a stream of indices to key value pairs:

Map<String, String> days = IntStream.range(0, shortNames.length).boxed()
    .collect(Collectors.toMap(i -> shortNames[i], i -> longNames[i]));

有一些第三方 Java 库包含一个zip"函数,用于获取两个流并生成从一个流到另一个流的映射.但实际上,它们只是实现与上述代码相同的事情的更简洁的方法.

There are some third party Java libraries that include a 'zip' function to take two streams and produce a map from one to the other. But really they are just neater ways of achieving the same thing as the code above.

这篇关于如何在 Java 中将两个数组映射到一个 HashMap?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆