java - 如何在java中的arraylist中的每个第三个元素之后添加换行符? [英] How to Add newline after every 3rd element in arraylist in java?
问题描述
我的程序需要在数组列表中的每个第三个元素之后添加换行符.这是我的输入文件,其中包含以下数据:
My program need to add newline after every 3rd element in the arraylist. Here is my input file which contain the following data:
934534519137441534534534366, 0796544345345345348965,796345345345544894534565, 734534534596544534538965,4058991374534534999999、34534539624、91953413789453450452、9137534534482080, 9153453459137482080, 405899137999999,9653453564564524、91922734534779797、0834534534980001528、823423985346356343430001528、405899137999999、9191334534643534547423752、3065345782642564522021, 826422205645345345645621,40584564563499137999999, 953453345344624, 3063454564345347,919242353463428434451, 09934634634604641264, 990434634634641264,40346346345899137999999, 963445636534653452, 919234634643325857953,91913453453437987385, 59049803463463453455421, 405899137534534999999,9192273453453453453758434,
934534519137441534534534366, 0796544345345345348965, 796345345345544894534565, 734534534596544534538965 , 4058991374534534999999, 34534539624, 91953413789453450452, 9137534534482080, 9153453459137482080, 405899137999999, 9653453564564524, 91922734534779797, 0834534534980001528, 82342398534 6356343430001528, 405899137999999, 9191334534643534547423752, 3065345782642564522021, 826422205645345345645621, 40584564563499137999999, 953453345344624, 3063454564345347, 919242353463428434451, 09934634634604641264, 990434634634641264, 40346346345899137999999, 963445636534653452, 919234634643325857953, 91913453453437987385, 59049803463463453455421, 405899137534534999999, 9192273453453453453758434,
它会继续多行.
public class MyFile {
private static final Pattern ISDN =Pattern.compile("\\s*ISDN=(.*)");
public List<String> getISDNsFromFile(final String fileName) throws IOException {
final Path path = Paths.get(fileName);
final List<String> ret = new ArrayList<>();
Matcher m;
String line;
int index = 0;
try (
final BufferedReader reader = Files.newBufferedReader(path, StandardCharsets.UTF_8);) {
while ((line = reader.readLine()) != null) {
m = ISDN.matcher(line);
if (m.matches()) {
ret.add(m.group(1));
index++;
if(index%3==0){
if(ret.size() == index){
ret.add(m.group(1).concat("\n"));
}
}
}
}
return ret;
}
}
}
推荐答案
我将您的代码更改为使用新"Java 7 文件 I/O 进行读取,并更正了行分隔符的使用以及一些格式.在这里,我在完成后遍历列表.如果它真的很长,你可以在构建它时迭代它.
I changed your code to read using the "new" Java 7 files I/O and corrected the use of a line separator, along with some formatting. Here I iterate over the list after it was completed. If it is really long you can iterate over it while constructing it.
public class MyFile {
private static final Pattern ISDN = Pattern.compile("\\s*ISDN=(.*)");
private static final String LS = System.getProperty("line.separator");
public List<String> getISDNsFromFile(final String fileName) throws IOException {
List<String> ret = new ArrayList<>();
Matcher m;
List<String> lines = Files.readAllLines(Paths.get(fileName), StandardCharsets.UTF_8);
for (String line : lines) {
m = ISDN.matcher(line);
if (m.matches())
ret.add(m.group(1));
}
for (int i = 3; i < ret.size(); i+=4)
ret.add(i, LS);
return ret;
}
}
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