查找arrayList中位数的问题 [英] Problems finding median of arrayList

问题描述

我不断收到 表达式的类型必须是数组类型，但它解析为 ArrayList arrayList 正在从我的测试类中提取数字.我使用 if 来确定 arrayList 中的值是偶数还是奇数，因为我可以使用两种不同的方法来确定中位数.但我无法使中值公式起作用.

I keep getting The type of the expression must be an array type but it resolved to ArrayList<Double> The arrayList is pulling numbers from my Test class. I made the if to determine if the arrayList has an even amount of values in it or an odd, for I could use the two different ways to determine the median. But I'm not able to get the median formula to work.

public class Data {

private ArrayList<Double> sets;

public Data(double[] set) {
    this.sets = new ArrayList<Double>();
    for (double i : set) {
        this.sets.add(i);
    }
}

public double getMedian(){
    Collections.sort(sets);

    double middle = sets.size()/2;
        if (sets.size()%2 == 1) {
           middle = (sets[sets.size()/2] + sets[sets.size()/2 - 1])/2;
        } else {
            middle = sets[sets.size() / 2];
        }
      return middle;
}

推荐答案

问题就在你找到中间的那一行:

The problem is on the line where you find the middle:

middle = (sets[sets.size()/2] + sets[sets.size()/2 - 1])/2;

您只能对数组使用 [index] 表示法.您需要使用 getter/setter 方法来访问 ArrayList 的元素.这应该有效:

You can use [index] notation only with arrays. You need to use getter/setter methods to access the elements of an ArrayList. This should work:

middle = (sets.get(sets.size()/2) + sets.get(sets.size()/2 - 1))/2;

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