将数组列表中的 JSON 转换为 ArrayList (Java) [英] Convert JSON inside an array list to an ArrayList (Java)

问题描述

我的输出如下所示:

<代码>{问题字段1":{"id":"customfield_10561","name":"错误免责声明",类型":空，"值":"
...
"},问题字段2":{"id":"customfield_13850","name":"ENV 工作类型 (DT)",类型":空，值":空},...问题字段9":{"id":"timespent","name":"花费的时间","类型":"空",值":空"}}

我想创建一个 ArrayList 并在其中添加所有名称(如果该值不为空).知道我应该如何在 Java 中执行此操作吗?

解决方案

假设您有以下 json 对象:

<代码>{"name":"约翰·多伊",年龄":100，"job":"科学家","地址":["地址 1","地址 2","地址 3"]}

要获取对象内部的不同字段，请创建一个 JSONParser 对象并使用 get() 方法获取该字段中保存的值

 试试 {FileReader reader = new FileReader("/path/to/file.json");JSONParser jsonParser = new JSONParser();JSONObject jsonObject = (JSONObject) jsonParser.parse(reader);String name = (String) jsonObject.get("name");System.out.println("名称为" + 名称);long age = (long) jsonObject.get("age");System.out.println("年龄为:" + age);JSONArray lang = (JSONArray) jsonObject.get("addresses");for (int i = 0; i < lang.size(); i++) {System.out.println("地址" + (i + 1) + ":" + lang.get(i));}} catch (FileNotFoundException fileNotFound) {fileNotFound.printStackTrace();} 捕捉(IOException io){io.printStackTrace();} catch (NullPointerException npe) {npe.printStackTrace();} catch (org.json.simple.parser.ParseException e) {e.printStackTrace();}}

My output looks like this :

{
  "IssueField1":{
                 "id":"customfield_10561", 
                 "name":"Bug Disclaimer", 
                 "type":null, 
                 "value":"<div style>...</div>"
                }, 

  "IssueField2":{
                 "id":"customfield_13850", 
                 "name":"ENV Work Type (DT)", 
                 "type":null, 
                 "value":null
                }, 
   .
   .
   .

  "IssueField9":{
                 "id":"timespent",
                 "name":"Time Spent", 
                 "type":"null", 
                 "value":"null"
                 }
}

I want to create an ArrayList and and add all names in it if the value is not null. Any idea how should I do this in Java ?

解决方案

Lets say you have the following json object:

{ "name":"john doe", "age":100, "job":"scientist", "addresses":["address 1","address 2","address 3"] }

to get the different fields inside of the object, create a JSONParser object and use the get() method to get the value held in that field

    try {
        FileReader reader = new FileReader("/path/to/file.json");
        JSONParser jsonParser = new JSONParser();
        JSONObject jsonObject = (JSONObject) jsonParser.parse(reader);
        String name = (String) jsonObject.get("name");
        System.out.println("The name is " + name);
        long age = (long) jsonObject.get("age");
        System.out.println("The age is: " + age);
        JSONArray lang = (JSONArray) jsonObject.get("addresses");
        for (int i = 0; i < lang.size(); i++) {
            System.out.println("Address " + (i + 1) + ": " + lang.get(i));
        }
    } catch (FileNotFoundException fileNotFound) {
        fileNotFound.printStackTrace();
    } catch (IOException io) {
        io.printStackTrace();
    } catch (NullPointerException npe) {
        npe.printStackTrace();
    } catch (org.json.simple.parser.ParseException e) {
        e.printStackTrace();
    }
}

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