如何在列表中搜索，我的列表如下所示:List<Object>myList = new ArrayList<Object>() [英] How to search in an List and my List is look like : List&lt;Object&gt; myList = new ArrayList&lt;Object&gt;()

问题描述

我想在一个列表中搜索，我的列表看起来像

I want to search in a List and my List is look like

List<Employee> oneEmp= new ArrayList<Employee>();
List<Employee> twoEmp= new ArrayList<Employee>();



oneEmp= [Employee [eid=1001, eName=Sam Smith, eAddress=Bangluru, eSalary=10000000], Employee [eid=0, eName=, eAddress=, eSalary=null], Employee [eid=1003, eName=Amt Lime, eAddress=G Bhagyoday, eSalary=200000], Employee [eid=1004, eName=Ash Wake, eAddress=BMC, eSalary=200000], Employee [eid=1005, eName=Will Smith, eAddress= Delhi, eSalary=200000], Employee [eid=1006, eName=Shya Ymwar, eAddress=Madras, eSalary=50000], Employee [eid=1007, eName=Nag Gam, eAddress=Pune, eSalary=10000000], Employee [eid=1008, eName=Arti, eAddress=Delhi, eSalary=10000000]]

twoEmp= [Employee [eid=0, eName=null, eAddress=null, eSalary=100000], Employee [eid=0, eName=null, eAddress=null, eSalary=50000], Employee [eid=0, eName=null, eAddress=null, eSalary=200000]]

我正在使用这样的代码:-

I am using code like this:-

for(Employee two : twoEmp){
        for (Iterator<Employee> iterator = oneEmp.iterator(); iterator.hasNext(); ) {
        Employee e = iterator.next();
        if (e.geteSalary() != null && two.geteSalary() != null && e.geteSalary().compareTo(two.geteSalary()) == 0) {
            finalEmpList.add(e);
        }
        }
    }

但这仍然需要 2 个 for 循环

But this still required 2 for loop

我使用的是 JAVA 1.6

I am using JAVA 1.6

我的员工类有属性:

//Employee class
int eid;
BigInteger eSalary;
String eName, eAddress;

现在我想获取 List who's Salary = 10000000 中的所有对象

Now I want to get all the objects in List who's Salary = 10000000

结果应该是:

[员工 [eid=1001，eName=Sam Smith，eAddress=Bangluru，eSalary=10000000]，员工 [eid=1007，eName=Nag Gam，eAddress=Pune，eSalary=10000000]，员工 [eid=1008，eName=Arti, eAddress=Del eSalary=10000000],.................................]

[Employee [eid=1001, eName=Sam Smith, eAddress=Bangluru, eSalary=10000000], Employee [eid=1007, eName=Nag Gam, eAddress=Pune, eSalary=10000000], Employee [eid=1008, eName=Arti, eAddress=Del eSalary=10000000],.........................]

我想在不使用任何循环或所需的最小循环的情况下实现此目的，因为数据会很大

I would like to achieve this without using any loop or minimum loop required because data will be large

推荐答案

是的，使用 流.

首先，考虑使用泛型集合:

First, consider using a generic collection:

List<Employee> employees = new ArrayList<>():
//add all employees to the list

现在您可以使用流 过滤你的列表

Now you can use streams to filter your list

List<Employee> filtered = employees.stream()    
            .filter(emp -> emp.getSalary() == 10000000)
            .collect(Collectors.toList());

可能 Stream 库仍在内部使用某种循环，但虽然它的实现对我来说是隐藏的，但我并不担心.

Probably Stream library is still using some kind of loop internally but while its implementation is hidden from me I do not worry.

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