Android 从 ArrayList<List<String>> 中删除项目 [英] Android Remove items from ArrayList&lt;List&lt;String&gt;&gt;

问题描述

如何从Arraylist中删除项目?

How to remove items from the Arraylist?

final ArrayList<List<String>> finalArrayList = null;
buf="1,2,3,four,5,six,nine,10";
finalArrayList.add(Arrays.asList(buf.split(",")));
   for(int i = finalArrayList .size()-1 ; i >0; i--){
      for(int i1 = finalArrayList .get(i) .size()-1 ; i1 > 0; i1--){
         if(isNumeric(finalArrayList.get(i).get(i1))==true){
            Log.d("arra", finalArrayList.get(i).get(i1).toString());
            finalArrayList.remove(finalArrayList.get(i).get(i1));
         }
     }
  }
}

如果有人链接到声明和解释 tuts 也很棒.

It would also be great if someone link to declaration and explanation tuts.

我不知道它是否合法，但它有效.感谢 此视频 和此链接.

final ArrayList<List<String>> finalArrayList = null;
String[] strn = buf.split(",");
ArrayList<String> names = new ArrayList<String> ();

for(int i =0;i< strn.length;i++){
names.add(strn[i]);
//System.out.println(names);
}
Iterator<String> i = names.iterator();
while(i.hasNext()){
String s = i.next();
//System.out.println("Printing>>>" + s);
try{
    if(isNumeric(s)==true){
        System.out.println("Removing...");
        i.remove();
    }
    else{
        System.out.println("No numeric");
    }
}catch(Exception e){
    System.out.println("On Removing Error===>" +  e.getMessage());
}
}
finalArrayList.add(names);

推荐答案

 finalArrayList.remove(finalArrayList.get(i).get(i1));

这里 finalArrayList.get(i).get(i1) 会在 listi1th 位置给你 Stringcode> 位于 finalArrayList

Here finalArrayList.get(i).get(i1) will give you String at i1th position of list which is there at ith position in finalArrayList

您正在尝试从 List 的 ArrayList 中删除 String，您需要做这样的事情(好吧不是确定是否要删除它)

You are trying to remove String from ArrayList of List<String> you need to do something like this (Well not sure you want to remove it or not)

(finalArrayList.get(i)).remove(i1); 

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